The order increasing acidity of the solutions is; CH3COONa ≈ NaF < CH3COONH4 < NH4NO3.
An acidic solution is one whose pH lies between 0 to 6. A salt that undergoes hydrolysis to give an acid will have an acidic pH. Let us now consider the solutions to know which of them will give an acid solution.
The order increasing acidity of the solutions is; CH3COONa ≈ NaF < CH3COONH4 < NH4NO3.
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Answer:
The answer to the question is
In order of increasing acidity, we have
CH3COONa→NaF→NaNO3→CH3COONH4→NH4NO3
Explanation:
(i) NH4NO3 is an acidic salt as it consists of NH₃ and HNO₃. NH₃ is a weak base and HNO₃ is a strong acid pH = 5.4
(ii) NaNO3 PH7 produces a neutral solution when dissolved in water
(iii) CH3COONH4 Very concentrated solutions are acidic while low concentration 0.5 M are neutral, pH = 7
(iv) NaF basic as it is formed from weak acid and strong base. The strength of the basicity depends on the solution pH 7.4
(v) CH3COONa Basic in small concentration pH 8 or 9
Therefore we have in order of increasing acidity, CH3COONa→NaF→NaNO3→CH3COONH4→NH4NO3
The correct answer is meiosis.
(2) radium-226 (4) thorium-232
Answer: Option (1) is the correct answer.
Explanation:
A positron is represent by the symbol .
For example,
The decay reaction is as follows.
The reaction will be as follows.
Therefore, we can conclude that out of the given options positrons are spontaneously emitted from the nuclei of potassium-37.
b. using pure water
c. blowing on the hot water
d. putting the powder and hot water in a mixer
A , i think because pure water won't dissolve the powder fast.