Ralph sold brownies for ?$0.27 a piece in order to earn money to buy baseball cards. If the cards cost ?$0.81 per? pack, and if Ralph had no money left over after buying? them, what is the least number of brownies he must have? sold
Answers
Greetings!
Answer:
3 brownies
Step-by-step explanation:
To find this answer we need to divide the 0.81 by 0.27 to find out how many brownies total 0.81:
0.81 ÷ 0.27 = 3
So he needs to sell 3 brownies.
Hope this helps!
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whats x?
Answers
= 4x-8+x=7
= 4x+x-8=7
= 5x=7+8
= 5x=15 dividing both sides by 5
= x=15/5
= x=3
so x is 3
B.commutative
C.distributive
D.reflexive
Which answer is right !
Answers
Final answer:
Leila used the distributive property in the first step to solve the given equation, multiplying both terms in the parentheses by the fraction 2/3.
Explanation:
In this step, Leila applied the distributive property. The distributive property states that a(b + c) = ab + ac. This property allows us to multiply a single term by two or more terms within a parenthesis. In this case, Leila multiplied the fraction 2/3 by both 'x' (the variable) and '5' (the constant), inside the parentheses.
So, the equation went from 2/3 (x + 5) to (2/3 * x) + (2/3 * 5), which follows the rule of distributive property ab + ac when applied to the given equation.
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Answers
Hope I helped! <3
Answers
first you multiply 7 by 3 then add 2
21+2=23
now you can add the sign on 23/3 which gives us the answer of -23/3
Answers
81 - 27 = 54 houses remaining.
54 - 36 = 18 houses remaining.
There are 18 houses left to be sold.
Final answer:
There were 81 new houses. Initially, 1/3 of them were sold, leaving 54 houses. Later on, 2/3 of the remaining houses were sold, leaving a total of 18 houses left to be sold.
Explanation:
The subject of this question is Mathematics and it appears to be suitable for a Middle School level. The problem is about understanding fractions applied to a real-life situation, specifically the sales of new houses in a neighborhood.
Let's begin by working out how many of the 81 houses were sold last month. Because the question states that '1 over 3' were sold, this equates to 81 divided by 3, which is 27 houses. We then deduct this number from the total of 81 to find the remaining houses. So, 81 - 27= 54 houses remained.
In this month, '2 over 3' of the remaining houses were sold. So, we calculate 2/3 of 54. Multiply 54 by 2 and then divide this by 3 to get 36 houses being sold this month.
Subtracting these 36 houses from the remaining 54 (i.e., 54 - 36), we find that there are 18 houses left to be sold.
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