Answer:
A. Distributive Property
Step-by-step explanation:
I'm taking the exam right now. :)
B) mean
C) frequency
D).median Frequency distributions that are skewed to the right, what is the relationship of the mean and median?
Answer:
Median
mean>median
Step-by-step explanation:
When the data is skewed to right the suitable average is median. Median is suitable because it is less effected by extreme values and thus locate the center of the distribution perfectly. Here the salaries of basket players are skewed to right and the best measure of central tendency to measure the center of distribution is median.
When the frequency distribution is rightly skewed then the relationship of mean and median is that mean is greater than median that is Mean>median.
Hence when the distribution is skewed to right the best choice to measure the center of distribution is median and when the data is skewed to right mean is greater than median.
You must show all your working.
ML is 4.8cm
LN is 7.2 cm
angle N is 38 degrees
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Answer:
16.66 cm² or 8.49 cm²
Step-by-step explanation:
The law of sines is useful for this.
sin(N)/LM = sin(M)/LN
M = arcsin(sin(N)×LN/LM) = arcsin(sin(38°)×7.2/4.8)
M =67.44° or 112.56°
Angle L is the remaining angle, so will have one of two measures:
L1 = 180° -38° -67.44° = 74.56°
The area of that triangle is ...
A = (1/2)LM×LN×sin(74.56°) ≈ 16.66 . . . . cm²
or ...
L2 = 180° -38° -112.56° = 29.44°
The area of that triangle is ...
A = (1/2)LM×LN×sin(29.44°) ≈ 8.49 . . . . cm²
To calculate the area of triangle MNL, first calculate the size of angle LMN using the Cosine Rule. Then use that angle and the known side lengths in the formula for the area of a triangle (Area = 0.5 * a * b * sin(C)) to find the area.
To solve this, you need to first calculate the size of angle LMN. This can be done using the Cosine Rule, which states that cos(C) = (a² + b² - c²) / 2ab, where a and b are the sides enclosing angle C. Here, angle C would be LMN, and sides a and b would be ML and LN.
Applying the values from your question, the cosine of LMN would be cos(LMN) = (4.8² + 7.2² - 38²) / (2 * 4.8 * 7.2). After calculating the cosine of the angle, you can find the angle itself using the inverse cosine function, or arccos.
Once you have the size of angle LMN, you can calculate the area of the triangle using the formula Area = 0.5 * a * b * sin(C), where a and b are sides of the triangle and C is the included angle. So, the area of triangle MNL would be Area = 0.5 * ML * LN * sin(LMN).
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Answer:
5
Step-by-step explanation:
Plz mark brainliest!!!
What are the coordinates of the point B?
Step-by-step explanation:
mid point=(1+(-4),(-3+(-0.5)
------ ------------
2 2
.mid point =-³/2,3.5/2
Answer the following questions.
How many points was each part worth?
points
How many questions did Part A have?
questions
How many questions did Part B have?
questions
Answer:
1. How many points was each part worth?
- 12 points
2. How many questions did part A have?
- 2 questions
3. How many questions did Part B have?
- 3 questions
Step-by-step explanation:
We can set up our equation like this:
6x = 4y
In the above equation, x is representing the number of true/false questions and y is representing the nymber of multiple choice questions.
Now, the problem tells us that they want the least number of points possible so we know we need to use low numbers.
Since 6 is higher than 4, it's easier to go off of there.
6 x 1 = 6 4 is too big to go into 6 so we will move on.
6 x 2 = 12 4 goes into 12 3 times so we can use this.
Now that we've figured this out, we can put it in our equation:
6(2) = 4(3)
In the above equation, we can see that I've put 2 in for x because we multiplied 6 by 2 to get 12. I also put 3 in for y because we multiplied 4 by 3.
Now we can start with the questions:
1. How many points was each part worth?
Each part was worth 12 points because we can multiply 6 by 2 and get 12 or 4 by 3 and get the same thing
2. How many questions did part A have?
Part A had 2 questions because this is what x was when we multiplied by 6
3. How many questions did Part B have?
Part B had 3 questions because this is what y was when we multiplied by 4
Hope this helps!!
Each part is worth 12 points. Part A has 2 questions. Part B has 3 questions.
The problem states that the number of points for Part A is equal to the number of points for Part B, and we need to find the least number of points for which this is possible. Let's represent the number of questions in Part A as x. Since each true/false question is worth 6 points, the total points for Part A will be 6x. Similarly, let's represent the number of questions in Part B as y. Since each multiple choice question is worth 4 points, the total points for Part B will be 4y. To find the least number of points for which the two parts are equal, we need to find the smallest common multiple of 6 and 4.
The prime factorization of 6 is 2 x 3.
The prime factorization of 4 is 2 x 2.
From the prime factorization, we can see that the least common multiple (LCM) of 6 and 4 is 2 x 2 x 3 = 12.
Therefore, each part is worth 12 points.
To find the number of questions in Part A and Part B, we can substitute 12 for the total points in each part and solve for x and y:
6x = 12
x = 2
4y = 12
y = 3
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