For the given triangle, the cosine of angle A equals .
Step-by-step explanation:
Step 1; In the given triangle, the opposite side has a length of 9 units, the adjacent side has a length of 3√3 units while the hypotenuse of the triangle measures 6√3 units. To calculate the cosine of angle A we divide the adjacent side by the hypotenuse side.
cos A = .
Step 2; Length of the adjacent side = 3√3 units.
Length of the hypotenuse side = 6√3 units.
cos A = 3√3 / 6√3
cos A = .
To check we also have A = 60° and cos 60° = .
Answer:
City C is 12 times the population of city A.
Step-by-step explanation:
AI-generated answer
To find out how many times the population of city C is compared to city A, we first need to determine the population of city C.
Given that the population of city B is 1,560,000 and the population of city C is twice the population of city B, we can calculate the population of city C as follows:
Population of city C = 2 * Population of city B
= 2 * 1,560,000
= 3,120,000
Now that we know the population of city C is 3,120,000, we can compare it to the population of city A.
The population of city A is given as 2.6 * 10^5 (which is scientific notation for 2.6 multiplied by 10 raised to the power of 5).
To compare the population of city C to city A, we divide the population of city C by the population of city A:
Population of city C / Population of city A = 3,120,000 / 2.6 * 10^5
To simplify this calculation, we can express both numbers in the same format:
3,120,000 = 3.12 * 10^6 (since we move the decimal point 6 places to the right)
2.6 * 10^5 = 260,000 (as we move the decimal point 5 places to the right)
Now we can calculate:
Population of city C / Population of city A = 3.12 * 10^6 / 260,000
Dividing these two numbers, we get:
Population of city C / Population of city A = 12
Therefore, the population of city C is 12 times the population of city A.
Answer:
City C is 12 times the population of city A.
Step-by-step explanation:
Easy, the cat weighs 1.4 pounds :)
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