MATHEMATICS MIDDLE SCHOOL

Which choice is NOT a way to find 9 ÷ 4?A- 9/4 (these are fractions by the way)
B- 9 x (times) 1/4
C- 1/4 0f 9
D- 1/9 of 4
Please help me!

Answers

Answer 1
Answer: My bet is on D - 1/9 of 4 :)

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Solve, using the substitution method 2x+4y=16 x-7=-4yA. (0,-7)B. (0,7/4)C. (9,-1/2)D. (17,-5/2)PLEASE HELP ASAP !!
15 3/5 % written as a fraction in simplest form.
The left and right page numbers on anopen book add to 333. What are thepage numbers?and

What is y ? and how do you get it ?

Answers

you first do the opposite of what 4 is. so subtract on both sides. next since y is already being divided by 5 you need to do the opposite which is multiplying. so multiply on both sides and your answer will be y=60

Is a simple random sample (sometimes, always or never) valid?

Answers

A simple random sample is SOMETIMES valid. 

This is cuz it can be different in  another sample like the random on. It can be different options or different opinions. When its different it can be valid OR invalid. It can always be a different thought from a different set of people/animals/books or whatever the case is. That is why your answer would be SOMETIMES.

Hope I helped ya! 
A simple random sample is sometimes valid.

A car releases 19.6 pounds of carbon dioxide for every 1 gallon of gasoline burned. Estimate the number of pounds of carbon dioxide released if 14.5 gallons are burned.

Answers

In the given question, most of the information's are of immense importance. based on these information's, the required answer to the question can be found. It is already given that the car releases 19.6 pounds of carbon dioxide for 1 gallon of gasoline. The amount of carbon dioxide released for 14.5 gallons of gasoline needs to be found.
So
Amount of carbon dioxide released by
1 gallon of gasoline = 19.6 pounds
Then
Amount of carbon dioxide released by
14.5 gallons of gasoline = (19.6 * 14.5) pounds
                                       = 284.2 pounds
So an estimated 284.2 pounds of carbon dioxide will be released by 14.5 gallons of gasoline.

The standard normal curve shown here is a probability density curve for a continuous random variable. This means that the area underneath the entire curve is 1. What is the area of the shaded region between the two z-scores indicated in the diagram?

Answers

Answer with explanation:

The Curve given here is a probability density curve for a continuous random variable.

Area under the entire region of the curve = 1

Using the Standard normal table to obtain area occupied when Z values are given

Area of the normal curve, when ,Z =0.88, is =0.8106

Area occupied by normal curve ,when Z= -1.26, is =0.1038

So, Area of shaded Region

     Z_(0.88)-Z_(-1.26)=0.8106-0.1038\n\n=0.7068

Option D:→ 0.7068    

I used one of the statistical functions on my trusty TI-83 Plus calculator:


normcdf(-1.26, 0.88) = 0.707


Note that this is, as expected, between 0 and 1.

The piano measures 19/4 feet long does it fit in a 5 foot long space?

Answers

Answer:

Piano fits in the given space.

Step-by-step explanation:

Given: Length of Piano = (19)/(4)\,feet

           Length of Space 5 foot

To find: If piano fits in the space or not

Piano fits in the space if its length is less than length of space .i.e., 5 foot

length of piano = (19)/(4) feet

feet is just plural of foot

So, conversion of unit not needed

Length of piano is improper fraction ( fraction whose numerator is gretaer than denominator ) So, it ca be expressed in mixed fraction.

\implies(19)/(4)=4(3)/(4)

This shows that Piano's length is more than 4 but less than 5.

Therefore, Piano fits in the given space.
Yes it would because 19/4 simplified is 4 3/4 which is less than 5 feet so it woudl fit

on saturday jesse plays basketball for 2/3 hour. then he plays some more. he plays 2 1/3 hours in all. how much longer did jesse play basketball? Draw a model to represent the problem. Then solve. Explain how your model helps you solve the problem.

Answers

subtract 2 1/3 and 2/3 to get 2 1/3
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