You take out a loan for $550 at a rate of 4.5% for 3 years. At the end of 3 years, how much interest has accumulated on the loan?

Answers

Answer 1
Answer: 550 * 4.5% = 24.75

24.75 * 3 = 74.25

The loan has accumulated to $74.25

The total paid back would be $624.25

Hope I could help :)

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How much did a purse original cost if you bought it for $55.00 at 25% off

Answers

so 55=100%-25%
55=75%
divide by 3
18.333=25%
multiply both sides by 4
$73.33= 100%
it cost $73.33

What is the value of G? -25 divided by g= 25

Answers

negative divide or multiply by negative is negative
so g is -1
-25/g = 25

= -25 = 25g 
    /25    /25

g = -1


Can I get some help on this question please, and a a explanation on how you got the answer too.

Answers

Answer: choice A) 3 & 1/4 quarts

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Work Shown:

There are 2 x's over the "1/4", so 2*1/4 = 2/4 of a quart is drank in total by this group. Let P = 2/4

There are 5 x's over the "3/4", so 5*3/4 = 15/4 quarts is drank in total by this group. Let Q = 15/4

Subtract P and Q

Q - P = 15/4 - 2/4 = (15-2)/4 = 13/4

Convert the result to a mixed number

13/4 = (12+1)/4

13/4 = 12/4 + 1/4

13/4 = 3 + 1/4

13/4 = 3 & 1/4

Answer:

3 quarts

Step-by-step explanation:

Evan’s car gets approximately 20 miles per gallon. How many feet can he drive with 1 pint of gas?

Answers

In the question, it is already given that Evan,s car gets approximately 20 miles per gallon.
So In 1 gallon of gas, Evans car gets approximately = 20 miles.
We also know that
1 mile = 5280 foot
20 miles = 105600 foot
1 gallon = 8 pints
Then
we come to know that
In 8 pints Evan's car travels approximately = 105600 feet
In 1 pint Evan's car travels approximately = 105600/8 feet
                                                                   = 13200 feet
So Evan's car will travel 13200 feet in 1 pint of gas.
2.5 miles
your welcome

Brainliest answer to who ever answers this first. What is the slope, and what is the y-intercept of the line?
y=2/3x-4
slope=
y-intercept=

Answers

slope = 2/3
y-intercept = 4

A 500 g model train car traveling at 0.8 m/s collides with a 300 g stationary car. The cars hook up and move off down the track together. How fast are they going? ( also how do I do it )

Answers

Answer:

0.5ms^(-1)

Step-by-step explanation:

Let v be the speed after the collision of both the cars.

Now, momentum is given by: mass × velocity, then by equating the total momentum before and after the collision of the two cars, we get

500{*}0.8+300{*}0=(500+300)v

400+0=800v

400=800v

v=0.5ms^(-1)

Thus, they are moving at the velocity of 0.5ms^(-1)

Answer:

0.5 m/s

Step-by-step explanation:

A 500 g model train car traveling at 0.8 m/s collides with a 300 g stationary car.

Initial velocity of train, v_T=0.8\ m/s

Initial velocity of car, v_C=0\ m/s

Mass of train, m_T=500\ g

Mass of car, m_C=300\ g

The cars hook up and move off down the track together.

Let the final velocity of car and train, v_T=v_C=v

Using conservation of momentum,

Momentum before collision = Momentum after collision

m_T* v_T+m_C* v_C=(m_T+m_C)* v

500* 0.8+300* 0=(500+300)* v

v=(400)/(800)

v=0.5\ m/s

Hence, After collision they will going with 0.5 m/s