Slope = 4/3, (-2, 11)
Answers
Answer:
y = x +
Step-by-step explanation:
the equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y-intercept )
here m = , hence
y = x + c ← is the partial equation
to find c substitute (- 2, 11) into the partial equation
11 = - + c ⇒ c =
y = x +
← equation of line
Related Questions
Danielle bought a new diary for $12.80. She paid with a $20 bill. How much change did she get back? A. $32.80 B. $8.20 C. $7.20 D. $7.10
Please help!!! 50 points!!1) Which of the following sets represents the domain of the function shown? ((2,7),(15,13),(21,-4),(24,18))A) (-4, 2, 7, 13, 15, 18, 21, 24)B) ((7,2),(13,15),(-4,21),(18,24)C) (2,15,21,24)D) (-4,7,13,18)2) The table shows the outputs y for different inputs x:Input(x): 3,7,11,15Output(y): 4,7,8,10Part A) Do the data in this table represent a function? Justify your answer.Part B) Compare the data in the table with the relation f(x)=5x-21. Which relation has a greater value when x=11?Part C) Using the relation in Part B, what is the value of x if f(x)=99?
Factor each expession 63+81
Give a example of a multi-step equation for each of the following solution
Answers
Answers
Answer:
€800 = $1200
New exchange rate =
750/1200 = 1.6
Answers
Final answer:
In the analogy posed in the question, 'ready' is to 'prepared' as 'unmindful' is to 'neglectful'. That is, just as being ready is synonymous with being prepared, being unmindful is synonymous with being neglectful.
Explanation:
In English language, there is a type of analogy where a pattern of word pairs is presented and the pattern is to be completed with another pair of words that follows the same relation. In your question, 'ready is to prepared as unmindful is to....', therefore, we are trying to find a word that is to 'unmindful' as 'prepared' is to 'ready'.
When someone is 'ready', it means they are 'prepared'. In a similar way, when someone is 'unmindful', it means they are 'unprepared' or 'neglectful'. Therefore, 'unmindful is to neglectful' is the correct analogy to the given question, following the same pattern as the 'ready-prepared' analogy.
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Final answer:
The question seeks to find a word that is to 'unmindful' as 'ready' is to 'prepared'. This is looking for a word that shares a similar relationship, in this case, the word 'negligent'.
Explanation:
The question is a form of analogy or comparison where you are asked to find a word that is to 'unmindful' as 'ready' is to 'prepared'. In other words, you are looking for a word that has a similar relationship to 'unmindful' as 'prepared' does to 'ready'. When you are 'ready' you are 'prepared'. Therefore, when you are 'unmindful' you can be seen as being 'negligent' because both words signify a lack of attention or thoughtfulness.
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Answers
Simplify
3 - 7n^2 + 3n^3 - (6n^3 - 1 - 5n^2)
Simplify brackets
3 - 7n^2 + 3n^3 - 6n^3 + 1 + 5n^2
Collect like terms
(3 + 10) + (-7n^2 + 5n^2) + (3n^3 - 6n^3)
Simplify
4 - 2n^2 - 3n^3
Answer:
-3n^3 - 2n^2 + 4.
Step-by-step explanation:
(3-7n^2+3n^3)-(6n^3-1-5n^2)
First distribute the negative over the second parentheses:
= 3 - 7n^2 + 3n^3 - 6n^3 + 1 + 5n^2
Now simplify like terms:
= -3n^3 - 2n^2 + 4 (answer).
B.m<1
C.m<-1
D.m<13
n - 8>5
A. n>13
B. n>3
C. n>-3
D. n>-13
p+5<10
A. p<-15
B .p<5
C. p<15
D. p<-5
Answers
Answer:
M<13, n > 13, p < 5
Step-by-step explanation:
We are to solve M - 7<6 for the variable M. To do this, add 7 to both sides, obtaining M < 13 (Answer D).
We are to solve n - 8 > 5 for n. To do so, add 8 to both sides:
n > 13 (Answer A).
We are to solve p + 5 < 10 for p. To do so, subtract 5 from both sides:
p < 5 (Answer B)
Outcome Club Diamond Heart Spade
Number of trials 8 12 11 9
A.
23%
B.
25%
C.
30%
D.
42%
A jar contained 6 red marbles, 10 green marbles, and 8 blue marbles. A marble was selected at random, the color was recorded, and the marble was placed back in the jar. The table shows the results after 50 trials.
What was the relative frequency of selecting a red marble? Round to the nearest percent, if necessary.
Outcome Red Green Blue
Number of trials 10 24 16
A spinner has five sections, labeled A, B, C, D, and E. The spinner is spun 84 times, and the results are recorded in the table.
What is the experimental probability of the spinner’s landing on A? Round to the nearest percent, if necessary.
Outcome A B C D E
Number of trials 14 20 18 15 17
A.
22%
B.
20%
C.
17%
D.
14%.
A jar holds 42 yellow and 14 purple crayons. A crayon is pulled out of the jar at random and then placed back in the jar.
How many times can you expect that a purple crayon will be pulled out of the jar in 140 tries?
A.
14
B.
20
C.
35
D.
47
A bin contains yellow and black balls. A ball is selected at random and then placed back in the bin. The results are recorded after 10 trials, 50 trials, and 150 trials. The results are recorded in the table.
Based on the table, how many times can you expect that a yellow ball will be selected in 300 tries?
Outcome Number of trials
10 50 150
Yellow 9 32 135
Black 1 18 15
Answers
first question is C: 30% (12/40=0,3)
The second question is 20% (10/50)
The third one is 16.66666, that's 17 % (14/84)
In the forth one, the purple crayons form 14/(14+42)=14/56=2/8=1/4, that's 25 %
So the purple crayons are 25 % of the total. SO in 140 trials, they should be pulled out 140*25%=140*1/4=35 times.
In the last one: after 10 trials it seemed that yellow balls were 90%. After 50 (which is a better measure yello balls seem to be 32/50=64%. After 150 trials it was 90 % again/.
I think this makes it likely that in 300 trials the balls will be taken 90% of times, that is 270 times.
B. 20%
C. 17%
I only know these