Enter your answer, as a decimal. Do NOT round.
3. The function f(x)=5000(0.98)^0.3x represents the number of white blood cells, per cubic millimeter, in a patient x days after beginning treatment for a virus.
What is the average rate of change in white blood cells between days 1 and 5?
(A) −29.75 mm^3/day
(B) −34.75 mm^3/day
(C) −282.47 mm^3/day
(D) −353.08 mm^3/day
4. The function f(x)=60(1.5)^x models an animal population after x years.
How does the average rate of change between Year 3 and Year 6 compare to the average rate of change between Year 0 and Year 3?
(A) The average rate of change is 3.375 times as fast.
(B) The average rate of change is 3 times as fast.
(C) The average rate of change is 1.5 times as fast.
(D) The average rate of change is 2.25 times as fast.
Answer:
The last one is B.
Step-by-step explanation:
For this case we have that by definition, the midpoint of a segment is given by:
We have the following ordered pairs:
Therefore, substituting values we have:
Rewriting we have:
Answer:
the coordinates of the midpoint of XY
Answer:
Angle A = 98.1°
Angle B = 59.5°
Angle C = 22.4°
Step-by-step explanation:
When given vertices (x1,y1) ,(x2,y2), we would be using the formula:
√(x2 - x1)² + (y2 - y1)²
ABC has vertices A(-1,6), B(2,10) and C(7,-2)
Side AB = A(-1,6), B(2,10)
√(x2 - x1)² + (y2 - y1)²
= √(2-(-1))² + (10 - 6)²
= √(3² + 4²)
= √9+16
= √25
= 5
Side BC = B(2,10), C(7,-2)
√(x2 - x1)² + (y2 - y1)²
√(7-2)² + (-2 - 10)²
= √5² +(-12)²
= √(25 + 144)
= √169
= 13
Side AC = A(-1,6), C(7,-2)
√(x2 - x1)² + (y2 - y1)²
√(7-(-1))² + (-2 - 6)²
= √6² +(-8)²
= √(64 + 64)
= √128
= 11.314
To find the measure of each angle we would be using the cosine rule
Where
a² = b² + c² - 2bc × Cos A
b² = a² + c² - 2ac × Cos B
c² = a² + b² - 2ab × Cos C
Sketching a triangle we find out that
Side AB = c = 5
Side AC = b = 11.314
Side BC = a = 13
Hence
1) for Side BC = a
a² = b² + c² - 2bc × Cos A
Cos A = b² + c² - a²/ 2bc
Cos A = 11.314² + 5² -13²/(2 × 11.313 × 5)
A = arc cos[(11.314² + 5² -13²)/(2 × 11.313 × 5)]
A = 98.13°
To the nearest tenth = 98.1°
2) for Side AC = b
b² = a² + c² - 2ac × Cos B
Cos B = a² + c² - b²/ 2ac
Cos B = 13² + 5² - 11.314/2 × 13 × 5
B = arc cos[ (13² + 5² - 11.314)/(2 × 13 × 5)]
B = 59.49°
To the nearest tenth = 59.5°
3) for Side AB = c
c² = a² + b² - 2ab × Cos C
Cos C = a² + b² - c²/ 2ab
Cos C = 13² + 11.314² - 5²/ 2 × 13 × 11.314
C = arc cos[(13² + 11.314² - 5²)/ (2 × 13 × 11.314)]
C = 22.38°
To the nearest tenth = 22.4°