tiny time has decided to make 288 tricycle each day. how many tricycle seats, wheels ,and pedals are needed ?
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seats- 288
wheels- 864
pedals- 576
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0. Give an example of how an organism can use surface tension.
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(1) bromine (3) francium
(2) cesium (4) iodine
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Answers
Answer:
Mg²⁺ cation
Br⁻ anion
Explanation:
Magnesium is present in group two of periodic table.
It is alkaline earth metal.
It has two valance electrons.
Thus by losing two valance electrons it complete the octet. The common oxidation state of magnesium is +2.
The bromine is present in group seventeen.
It has seven valance electrons.
It is the member of halogen family.
To complete the octet bromine required one electron. By gaining the one electron it showed -1 oxidation state.
When bromine combine with magnesium both formed MgBr₂.
The one atom of Mg have +2 oxidation state while bromine have -1 that's why to make the overall compound neutral two bromine atoms combine with one atom of magnesium.
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If 2.70 mol C2H4 is reacted with 6.30 mol O2 identify the limiting reagent
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The limiting reagent is O₂.
Firstly, write the balanced chemical equation:
C₂H₄ + O₂ → CO₂ + H₂O
Then, we need to write the mole ratio of the reactants
The theoretical mole ratio is given by the coefficients of the balanced chemical equation: 3 moles of O₂ react with 1 mol of C₂H₄
Now, let's write the mole ratio of the substances available
≈
We concluded that,
Since, the ratio of the O₂ to C₂H₄ available is less than the theoretical ratio of O₂ needed to react with C₂H₄, the former is not enough: it will be consumed before the other reagent and it is the limiting reactant.
Hence, the limiting reagent is O₂.
Learn more:
Answer:
- The limiting reagent is O₂.
Explanation:
1. Write the balanced molecular equation:
2. Write the mole ratio of the reactants
The theoretical mole ratio is given by the coefficients of the balanced molecula equation: 3 moles of O₂ react with 1 mol of C₂H₄
3. Write the mole ratio of the substances available
4. Conclusion
Since the ratio of the O₂ to C₂H₄ available is less than the theoretical ratio of O₂ needed to react with C₂H₄, the former is not enough: it will be consumed before the other reagent and it is the limiting reactant.
Hence, the limiting reagent is O₂.