In a binary system with a main-sequence star and a brown dwarf, we can determine their masses by analyzing their radial velocity curve and measuring the Doppler shifts of their spectral lines. Kepler's law can then be used to calculate the sum of their masses.
The question is about a binary system containing a main-sequence star and a brown dwarf. We can determine the masses of the stars in a spectroscopic binary by analyzing their radial velocity curve. By measuring the Doppler shifts of the spectral lines, we can calculate the orbital speed of each star and use Kepler's law to calculate the sum of their masses.
#SPJ12
The orbital speed and separation of a binary system composed of a main-sequence star and a brown dwarf can be utilized to infer their respective masses. This is accomplished by studying the Doppler effect from the spectral lines of the system and applying Kepler's third law. Greater mass is found to exhibit slower orbital speed.
The main-sequence star and the brown dwarf form a binary system with an orbital period of 1 year and an average separation of 1 Astronomical Unit (AU). The Doppler shifts of the spectral lines from the main-sequence star and the brown dwarf indicate that the orbital speed of the brown dwarf in the system is 22 times greater than that of the main-sequence star.
We can estimate the masses of the stars in this binary system using the formula based on Newton's reformulation of Kepler's third law: D³ = (M₁ + M₂)P², where D represents the semimajor axis in AU and P represent the period in years. From this, we can calculate the sum of the masses of the two stars. Given the difference in orbital speeds, the main-sequence star has a higher mass to result in a slower speed, and the brown dwarf has a smaller mass to result in the higher speed.
In conclusion, by analyzing the radial velocity curve and using Kepler's third law, we can estimate the masses of the stars in a binary system.
#SPJ11
b. energy barrier
c. collision group
d. transition state
Among the choices above, the one that is most closely related to an activated complex is the transition state. The answer is letter D. This formation forms quickly and does not stay in a way compound is. It usually forms during the enzyme – substrate reaction.
B. Main sequence
C. Nebula
D. Protostar
The correct answer is D. Protostar.
Nuclear fusion in a star's lifecycle begins during the protostar stage. This is when the temperature and pressure of the protostar ignite nuclear fusion, transitioning into a main sequence star.
In the life cycle of a star, nuclear fusion begins when the star has reached the protostar stage. The initial stage in the development of a star is the nebula, which is a cloud of dust and gas. Over time, the nebula's materials collapse under gravity to form a hot core known as a protostar.
When the protostar's temperature and pressure rises, it triggers nuclear fusion and the star begins turning hydrogen into helium.
This marks the transition from a protostar to a main sequence star, which is the stage of stable nuclear fusion.
#SPJ3
The statement describes the interaction between the permanent magnets and the electromagnet in an electric motor is option D.
A substance which is negative charged at one end and positive charged at another end creating the magnetic field around it.
A bar is a magnet which can attract the particle which are charged. It has two poles North and South.
The permanent magnet create magnetic field very strong. The electromagnet is find in the electric motor. In the motor, loopmade up of conductor is rotated by the effect of magnetic field of permanent magnet.
Thus, the correct option is D.
Learn more about magnet.
#SPJ2
Answer:D
Explanation:AP3X
B. Perpendicular
C. Opposite
D. Parallel
Good afternoon,
B. Perpendicular
I hope this helped :)
b. the risk of cancer associated with eating GM food.
c. increased resistance of insects to pesticides because of the pesticides resistance of GM crops.
d. the loss of consumer support.