What is a tiltmeter?

Answers

Answer 1

Answer: A tiltmeter is an object to measure small movements.

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Which weather technology is used to gather pressure, wind speed, and other first-hand observations of hurricanes that are out at sea?

Answers

A weather technology is used to gather pressure, wind speed, and other first-hand observations of hurricanes that are out at sea is a weather station. A weather station is used on land and at sea to measure the different weather elements at various points or regions. They are equipped with a wide array of instruments that can either manually or automatically measure data.

Answer:

Recon-Aircraft

Explanation: It gathers Info firsthand.

Two point charges are separated by 6 cm. The attractive force between them is 20 N. Find the force between them when they are separated by 12 cm. (Why can you solve this problem without knowing the magnitudes of the charges

Answers

The force between the two point charges is "5 N".

Force and magnitudes:

The total of almost all of the forces operating on an item is referred to as the magnitude of force. When some of the forces operate in the same direction, this same magnitude rises. Whenever forces occur in opposite directions around an item, the amount of something like the force diminishes.

Distance between charges, d = 6 cm

Attractive force, F = 20 N

Separated, d' = 12 cm

We know the formula,

F = $k (q_1q_2)/(d^2)$

or,

F $\propto (1)/(d^2)$ ...(Equation 1)

New force will be:

F' $\propto (1)/(d'^2)$ ...(Equation 2)

From "Equation 1" and "Equation 2", we get

→ $(F)/(F') =(d'^2)/(d^2)$

By substituting the values,

$(20)/(F') =(12^2)/(6^2)$

$(20)/(F') =(144)/(36)$

F' = 5 N

Thus the approach above is appropriate.

Find out more information about force here:

brainly.com/question/388851

Answer:

The force between them when they are separated by 12 cm is 5 N.

Explanation:

Distance between two point charges, d = 6 cm

The attractive force between them is 20 N, F = 20 N

Let F' is the force between them when they are separated by 12 cm, d' = 12 cm

The force between point charges is given by the formula as :

$F=k(q_1q_2)/(d^2)$

$F\propto (1)/(d^2)$ ........(1)

New force,

$F'\propto (1)/(d'^2)$ ............(2)

From (1) and (2) :

$(F)/(F')=(d'^2)/(d^2)\n\n(20)/(F')=(12^2)/(6^2)\n\nF'=5\ N$

So, the force between them when they are separated by 12 cm is 5 N. Hence, this is the required solution.

When creating any map, what four basic elements should you include?

Answers

You must include a key, title, date of publication, and scale.

Title,Scale,Date of Publication,North Arrow (Legend,Location Information,and Source of Information)

as a drivers vehicle approaches an intersection at 20 m/s the driver applies the brakes in order to stop creating a uniform acceleration of 2.3 m² calculate the time required to stop

Answers

Answer:

8.70 seconds.

Explanation:

1. Use the kinematic equation: v = u + at,

v = final velocity

u = initial velocity

a = acceleration

t = time.

Find variables and numbers:

v = ?

u = 20 m/s

a = -2.3 m²

v = 0 m/s

Rearrange values: t = (v - u) / a.

Plugging in the values: t = (0 - 20) / (-2.3) = 20 / 2.3

Gravitational potential energy is a form of potential energyA.) caused by gravity alone.
B.) caused by gravity and that depends on an object's position and mass.
C.) caused by gravity and that depends on an object's mass, but not its position.
D.) caused by gravity and that depends on an object's position, but not its mass.

Answers

B. The mass and height dictates the force gravity will pull on it

Suppose that at room temperature, a certain aluminum bar is 1.0000 m long. The bar gets longer when its temperature is raised. The length l of the bar obeys the following relation: l=1.0000+2.4×10−5T, where T is the number of degrees Celsius above room temperature. What is the change of the bar's length if the temperature is raised to 14.1 ∘C above room temperature?

Answers

Answer:

0.00034 m

Explanation:

Since the length of the aluminium bar, L is given by , L = 1.0000 + 2.4 × 10⁻⁵T and T = 14.1°C, we substitute the value of T into L. So, we have L = 1.0000 + 2.4 × 10⁻⁵ × 14.1°C = 1.0000 + 0.0003384 = 1.0003384 m. The change in length is thus 1.0003384 - 1.0000 = 0.0003384 m ≅ 0.00034 m

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