What number is 1/10 the value of 237

Answers

Answer 1
Answer:

23.7 number is 1/10 the value of 237.

the given value is 237.

We have to find the (1)/(10) part of 237.

First we will learn what is one-tenth.

One tenth is the same as one out of ten parts. It is a common fraction that means the same as 10% or 0.1.

So, the ten percent of 237 will be,

237* (10)/(100) =23.7

Hence the required value is 23.7 .

For more details on one-tenth follow the link:

brainly.com/question/14028047

Answer 2
Answer: 1/10 × 237
= 237/10
= 23.7

1/10 the value of 237 is 23.7.

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Answers

Answer:

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Step-by-step explanation:

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Mrs.Morales wrote a test with 15 questions covering spelling and vocabulary.spelling questions (x )are worth 5 points and vocabulary questions (y)are worth 10 points.the maximum number of points possible on the test is 100.

Answers

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One serving of this cereal provides you with 160 mg of sodium. This is 7% of your body's daily needs. How many milligrams of sodium equal 100%?

Answers

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1+4 = 5
2+5 = 12
3 + 6 = 21
8 + 11= ?

Answers

The correct answer is 40. Hope that helps!
(1x4)+1=5
(2x5)+2=12
(3x6)+3=21
(8x11)+8=96

I'm not sure but that's my guess

Number 7 please help

Answers

7) Draw a quadrilateral with 1 pair of parallel side. What special quadrilateral have you drawn?

Properties of a quadrilateral:
1) has four sides or edges
2) has four vertices or corners
3) interior angles add up to 360°

US definition: A trapezoid is a quadrilateral that has 1 pair of parallel sides.
UK definition: A trapezium is a quadrilateral that has 1 pair of parallel sides.


If 5 Pounds of Apples Cost $4.45, Then:A. What Is The Price Per Pound?

B. What Is The Cost For 8 Pounds Of Apples?

Thanks So Much!! I Appreciate It!!

Answers


for you will divide 4.45 to get the price per pound which is .89 
for B you would multiply what we found the price per pound .89 by 8 to get 7.12
A.89 cents per pound I did 4.45 divided by 5
  
B. I did 89 x 8 =$7.12
                                                                                                  Hope this helped :)