B. One real solution
C. Two imaginary solutions
What is the value of U?
What is the value of W?
What is the value of V?
What is the value of Z?
What is the value of x?
What is the value of y?
Answer:
The value of U = 4
The value of W = -6
The value of V = 5
The value of Z = 1
The value of x = 3
The value of y =2
Step-by-step explanation:
Given:
20a³b³ – 24a⁵b² + 4a³b²
Solution:
Lets first factorize this expression:
20a³b³ – 24a⁵b² + 4a³b²
= −24a⁵b² + 20a³b³ +4a³b²
Taking 4a³b² common
= 4a³b² (−6a² + 5b + 1) ___ (1)
Now you can see this expression takes the form:
Ua^xb^y (Wa^2 + Vb+ z), where U > 0.
Now you can clearly see from (1)
The value of U is 4
The value of W is -6
The value of V is 5
The value of Z is 1
The value of x is 3
The value of y is 2
However if we take minus common from above equation:
20a³b³ – 24a⁵b² + 4a³b²
= −24a⁵b² + 20a³b³ +4a³b²
Taking 4a³b² common
= - 4a³b² (6a² - 5b - 1) ___ (1)
In this case the value of U is - 4, W is 6 , V is -5, Z is -1 , x is 3 and b is 2
. The variable costs will be
$10.50
per book. The publisher will sell the finished product to bookstores at a price of
$25.25
per book. How many books must the publisher produce and sell so that the production costs will equal the money from sales?
Answer:
Second option is the right choice.
Step-by-step explanation:
Divide the second equation by -5 and you'll get the equation same as first equation.
So, it has infinite many solutions.