Solve the inequality 4y > 2(3y + 1) and explain your solution. *

Answers

Answer 1
Answer: 4y \ \textgreater \ 2(3y + 1) \n \n 2y \ \textgreater \ 3y + 1 \n \n 2y - 3y \ \textgreater \ 1 \n \n -y \ \textgreater \ 1 \n \n y \ \textless \ -1 \n \n

The final result is: y < -1.

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The scale in the drawing is 2cm 5m. what are the length and width of the actual room. __________14inch
|
7inch|

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your answer would be 7inches

21/8 as a mixed number

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divide 21 by 8. and then whatever the reminder comes will go as the whole number
and the reminder will be the numerator and the number 8 will be the denominator.
the answer is 2 5/8
2 is the whole number, 5 is the numerator and 8 is the denominator

Hope this helps!
Well, all you would have to do is divide 21 into 8, (21 divided by 8), and the remainder will become your new numerator, and the divisor, (8), will be your denominator, and the whole answer will be your whole number, so your mixed number will be 2 5/8, because 21 divided by 8 = 2, 2 times 8 = 16, 21 - 16 = 5, 2 is your whole number, 5 is your numerator, and 8 is your divisor. =)
I hope I helped! =D

what is 18/5 as a fraction and as a decimal?

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Decimal: 3.6
Fraction: 18/5 or 3&3/5
As a decimal it is 3.6
while asa mixed fraction it is 3 3/5

6/10 is bigger, less or equal than 3/4??

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less than. i'm almost positive that is the answer
6/10 is less than 3/4

I really need help and fast

Answers

yeah adb is at an acute angle so say adb is congruent to CDC by an obtuse angle

Can a right triangle have a leg that is 10 meters long and a hypotenuse that is 10 meters long

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lets see
a and b are legs
c=hypotnuse
a^2+b^2=c^2
10^2+b^2=10^2
100+b^2=100
minus 100 both sides
b^2=0
b=0
false, if you have a leg legnth 0, then they lines are right on top of each other




no cannot
Solutions

To solve this problem we have to use the Pythagorean theorem. You can only use the Pythagorean theorem in Right Triangles. The longest side of the triangle is called the "hypotenuse". C² is the longest side so it is the hypotenuse . To calculate c² we have to do α² + β² = c². 

Given 

α² = 10 
c² = 10 

Solve 

α² + β² = c² 
α² (10²) + β² = c² (10²) 
100 + β² = 100 
β² = 100 - 100 = 0 

Simplify 

A right triangle can not have a leg that is 10 meters long and a hypotenuse that is 10 meters long.