Answer:
This reaction is completed by a double displacement
A double displacement occurs when two different salts are mixed in an aqueous state, since when they dissolve a salt their ions are dissociated and when mixed with another salt in an aqueous state they combine and form two new compounds
Double displacement reactions
b. S
c. H₂
d. Ne
e. C
The substance that combined with the oxygen to form a greenhouse gas has been carbon (C). Thus, option E is correct.
The greenhouse gases have been responsible for the entrapment of the sun's energy in the atmosphere, leading to the increase in the temperature of earth and making earth an appropriate place to live.
The greenhouse gases have been the carbon dioxide, methane, sulfur etc. that are able to entrap the energy.
The reaction of carbon with oxygen has been resulted in the formation of carbon dioxide. It has been a green house gas.
Thus, the substance that combined with the oxygen to form a greenhouse gas has been carbon (C). Thus, option E is correct.
For more information about greenhouse gas, refer to the link:
2. Calculate the moles of O in the sample.
Answer:
The answers are
C = 0.0895 moles
1. 0.02975 moles of N
2. 0.0299 moles O
Explanation:
Mass of sample = 2.18 g
Combustion yields 3.94 g of CO₂ and 1.89 g of H₂O
1.23 g of sample contains 0.235 g of N
3.94 g of CO₂ which contains one mole of C and two moles of O
Molar mass of CO₂ = 44 mass fraction of C = 12/44 = 0.273, Therefore mass of carbon in 2.18 g = 0.273×3.94 = 1.075 g
number of moles of C in sample = mass/(molar mass) = 1.075 g/(12.01 g/mol) = 0.0895 moles of C
(1) Mass of nitrogen, in 1.23 g of sample = 0.235
therefore mass in 2.18 g =0.235×2.18/1.23 = 0.4165 g
= 0.02975 moles of N
(2) To find the number of moles of oxygen in the sample we note that total mass of sample = 2.18 g containing only nitrogen, hydrogen, oxygen and carbon
Mass of hydrogen can be fround from 2/18×1.89 = 0.21 g
Mass of oxygen therefore = 2.18 -(0.21+0.4165+1.075) = 0.4785
number of moles = 0.475/16 = 0.0299 moles
Answer:
T₂ = 379.4 K
Explanation:
Given data:
Initial volume = 1.56 L
Initial temperature = 20°C (20+273 = 293 K)
Final volume = 2.02 L
Final temperature = ?
Solution:
The given problem will be solve through the Charles Law.
According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.
Mathematical expression:
V₁/T₁ = V₂/T₂
V₁ = Initial volume
T₁ = Initial temperature
V₂ = Final volume
T₂ = Final temperature
Now we will put the values in formula.
V₁/T₁ = V₂/T₂
T₂ = V₂T₁ /V₁
T₂ = 2.02 L × 293 K / 1.56 L
T₂ = 591.86 L.K / 1.56 L
T₂ = 379.4 K
(3) the mass of neutrons in grams
(4) the number of neutrons in grams
Answer: option (1) the atomic mass in grams.
Explanation:
1) The atomic mass is the mass in grams of one mole of atoms.
2) Hence, it is always the atomic mass of an element equal to the mass of one mole of atoms of such element. Therefore, the atomic mass of Au is the mass of one moles of atoms of Au.
3) Here are some examples:
i) Atomic mass of gold: 196.67 g/atoms, means that 196.97 grams of Au is one mole of Au.
ii) Atomic mass of hydrogen: 1.008 g/mol, means that 1.008 grams of H is one mole of H.
iii) Atomic mass of oxygen: 15.999 g/mol, means that 15.999 grams of O is one mole of O.
iv) Atomic mass of lead: 207.2 g/mol, means that 207.2 grams of Pb is one mole of Pb.
Now you see it, the atomic mass in grams of an element is equal to one mole of the element.
(2) 19 protons and 42 neutrons
(3) 20 protons and 19 neutrons
(4) 23 protons and 19 neutrons
Answer:
27.3 L
Explanation:
To calculate the volume of the balloon at a certain height, we can use the combined gas law. The volume of the balloon at the new height is approximately 1.13 L.
To solve this problem, we can use the combined gas law, which states that the ratio of the initial pressure, volume, and temperature will be equal to the ratio of the final pressure, volume, and temperature.
Using the formula PV/T = constant, we can set up the equation (1.00 atm * 2.30 L) / (23.5 + 273.15 K) = (0.810 atm * V) / (12.0 + 273.15 K), where V is the volume of the balloon at the new height.
Simplifying the equation and solving for V, we find that the volume of the balloon at the new height is approximately 1.13 L.
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