Kay builds a 1/6 scale model of a train. The actual train is 42 1/2 feet long. How long is the model

Answers

Answer 1
Answer:  7 1/12 feet long..
42 1/2 * 1/6 = 7 1/12

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Consider the exponential function f(x) = 1/5(15x). What is the value of the growth factor of the function?a.1/5
b.1/3
c.5
d.15

Answers

Answer:

Option: d is the correct answer.

      d.   15

Step-by-step explanation:

We are given a exponential function as:

             f(x)=(1)/(5)(15^x)

We know that in general a exponential function is represented by:

        f(x)=ab^x

where a is the initial amount and b represents a growth factor if it is strictly greater than 1 and a decay factor if 0<b<1

Hence, the value of the growth factor of the function is:

                              d.   15

The answer would have to be 15.

Can someone help with geometry !! If m

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i can try to help you if you type the rest of your question!

What is the value of this expression when x = -5 and y = -3 (2)/(3) x^(3) y^(2)

Answers

Answer:

y = - 750

Step-by-step explanation:

Given

y = (2)/(3) x³y² ← substitute x = - 5, y = - 3 into the expression

  = (2)/(3) × (- 5)³ × (- 3)²

  = (2)/(3) × - 125 × 9 ( cancel the 3 and 9 )

  = 2 × - 125 × 3

  = - 750

At a benefit concert, fourteen bands have volunteered to perform but there is only enough time for six of the bands to play. How many lineups are possible?

Answers

There are 2,162,160 possible combination that could be made if there are 14 bands and only 6 slots available. This is computed using factorial. By using factorial we first need to identify the number of band and the number of slots available. It could be express as 14! - 8! or 14 x 13 x 12 x 11 x 10 x 9, which is equal to 2,162,160 combination.

2x^2-7x-15

put this function into standard form

Answers

Answer:

It is already in standard form. 2x^2-7x-15 is correct.

Step-by-step explanation:

The standard form of a quadratic equation (which this equation is since there is an x^2 term) is described as ax^2+bx+c=0, where a≠0.

What multiplies to be -18 and adds to be -9?

Answers

IMPORTANT:
If you're trying to factor a quadratic in Algebra I:
There are no two integers that can solve this problem!
Your quadratic is prime!

If you're trying to solve a quadratic (find x):
The factoring approach will not work for the same reasons listed above.
Try using splitting the middle or the quadratic formula instead.

Here's how you would solve it from a more advanced approach.
If you don't know what this stuff is, just ignore it.
ab = -18, a + b = -9
Find a in terms of b.
a = -9-b
Substitute this for a in the first equation.
(-9-b)b = -18
-9b-b² = -18
Multiply everything by -1 to get rid of all these negative signs.
b² + 9b = 18
Bring over that 18.
b² + 9b - 18 = 0
Apply the quadratic formula.
(a = 1, b = 9, c = -18)
(-b\pm√(b^2-4ac))/(2a)=(-9\pm√(9^2-4(1)(-18)))/(1*2)=(-9\pm√(81+72))/(2)=(-9\pm√(153))/(2)=\boxed{(-9\pm3√(17))/(2)}
If you need to write two distinct numbers, just write out one with a + and one with a - in place of the plus-minus sign.