Which of the following is a form of mechanical energy?a. internal energy
c. gravitational potential energy
b. chemical potential energy
d. electrical energy

Answers

Answer 1

Answer:

Gravitational potential energy is a form of mechanical energy.

What is Gravitational potential energy?

Gravitational potential energy is the energy possessed or acquired by an object due to a change in its position when it is present in a gravitational field.

If an object is at rest and doesn't involve elastic energy, then mechanicalenergy can be equal to gravitational potential energy.

To learn more about Gravitational potential energy here

brainly.com/question/3884855

#SPJ2

Answer 2

Answer: Okay so i believe that potential energy is mechanical but there are two answers with potential energy in it. Its a tough one but I think I would go with gravitational potential energy. Hope this helped!

Related Questions

What is the relationship among amplitude,crest,and trough?
The planet Pluto has 1/500 the mass and 1/15 the radius of Earth. What is the value of g on the surface of Pluto?(A) 0.3 m/s2 (B) 1.6 m/s2 (C) 2.4 m/s2 (D) 4.5 m/s2 (E) 7.1 m/s2
What is acceleration?a. change in velocity/change in time b. change in distance/change in time c. change in mass/change in volume d. change in pressure/change in time
Many scientists believe that the current period of global warming is related to increased levels of what?
what is the difference in the charges on a balloon rubbed in your hair and a glass rod rubbed with silk? why?

Which of these takes about 365 days to complete? Earth rotating once on its axis Earth rotating once on its axis Earth revolving once around the Sun Earth revolving once around the Sun the moon revolving once around Earth the moon revolving once around Earth the sun revolving once around Eart

Answers

Answer:

Earth revolving once around the Sun

Explanation:

The Earth is one of the planets that make up the Solar system. The earth undergoes two phenomena called "ROTATION" and "REVOLUTION". Rotation refers to the moving around of an object along its own axis while revolution refers to the moving of an object around another object.

The Earth rotates (along its axis) to produce the day and night (24 hours). However, the revolution of the Earth around the largest planetary body, which is the SUN, takes approximately 365 days to complete. Hence, the Earth's revolution around the sun produces the year (365 days).

An object is dropped from a height H above the ground. This free-falling object requires 1.02 s to travel the last 39 m before hitting the ground. From what height H above the ground did the object fall?

Answers

Answer:

H = 95.3 m

Explanation:

Let the height from which object fall down is H

so the total time to fall is given as

$H = (1)/(2)gt^2$

now it cover 39 m in last 1.02 s of its path

$H - 39 = (1)/(2)g(t - 1.02)^2$

so now we have

$(1)/(2)gt^2 - 39 = (1)/(2)g(t - 1.02)^2$

by solving above equation

$t = 4.41 s$

Now the total height is given as

$H = (1)/(2)gt^2$

$H = (1)/(2)g(4.41)^2$

H = 95.3 m

Salmon often jump waterfalls to reach theirbreeding grounds.
Starting 3.16 m from a waterfall 0.379 m
in height, at what minimum speed must a
salmon jumping at an angle of 37.6
◦
leave the
water to continue upstream? The acceleration
due to gravity is 9.81 m/s
2
.
Answer in units of m/s.

Answers

The problem corresponds to the motion of a projectile (the salmon), with initial speed $v_0$ , initial direction $\theta=37.6^(\circ)$ and vertical acceleration $g=9.81 m/s^2$ downward. The two equations which gives the horizontal and vertical position of the salmon at time t are

$S_x (t) = v_0 cos \theta t$ (1)

$S_y (t) = v_0 sin \theta t - (1)/(2)gt^2$ (2)

We can solve the problem by requiring Sx=3.16 m and Sy=0.379 m, the data of the problem.

Solving eq.(1) for t:

$t=(S_x)/(v_0 cos \theta)$

And substituting this expression of t into eq.(2), we get the following expression for $v_0$ :

$v_0 =\sqrt{(g S_x^2)/(2(tan \theta S_x -S_y)cos^2 \alpha)}$

And substituting the numbers into the equation, we find

$v_0 = 6.16 m/s$

In a cathode ray tube, the number of electrons that reach the fluorescent screen is controlled by the A. cathode.
B. grid.
C. anode.
D. deflecting plate.

Answers

In a cathode ray tube, the number of electrons that reach the fluorescent screen is controlled by the grid. The correct option among all the options given in the question is option "B".When current issupplied to the heater, it causes the cathode to emit electrons. The electronspass through opening of the grid before reaching the anode. By controlling thenumber of electrons passing through the grid, the number of electrons reachingthe anode can also be controlled.

Answer: B. GRID

Explanation: I JUST TOOK THE PF EXAM AND GOT IT CORRECT!!!!

a car travelling at 36 km/hr due north turns west in 5 s under constant acceleration and maintains the same speed. the acceleration of the car is

Answers

If acceleration is constant we calculate it from the formula:
a= $(v)/(t)$
v=36 $(km)/(h)$
t=5s
We convert units:
t=5s= $(1)/(12)$ h
a= $(36)/( (1)/(12))$ =432 $(km)/(h²)$ =0,033333333333333 $(m)/( s^(2) )$