A builder planned to build houses. Each house will be built on 5/6 of an acre. How much land would be needed for 7 houses? The builder began with 10 acres of land . After 7 houses were built, how much land was left unused?

Answers

Answer 1
Answer:

Answer:

5(5)/(6)\approx 5.833 acres of land would be needed for 7 houses.

(25)/(6)\approx 4.17 acres of land was left unused.

Step-by-step explanation:

We have been given that each house will be built on 5/6 of an acre.

To find the area it will take to build 7 houses, we will multiply area need to build one house by 7 as:

(5)/(6)* 7

(35)/(6)

5(5)/(6)\approx 5.833  

Therefore, 5(5)/(6)\approx 5.833 acres of land would be needed for 7 houses.

Since builder began with 10 acres of land, so we can find the unused land by subtracting 5(5)/(6)  from 10 as:

10-5(5)/(6)

10-(35)/(6)

(10*6)/(6)-(35)/(6)

(60)/(6)-(35)/(6)

(60-35)/(6)

(25)/(6)

(25)/(6)\approx 4.17

Therefore, (25)/(6)\approx 4.17 acres of land was left unused.

Answer 2
Answer: For 7 houses you will need 5.83 acres of land and the builder will have 4.16 acres of land unused 

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Round 636 to the nearest ten and hundred

Answers

Rounding 636 to nearest ten will give 640 and rounding 636 to nearest hundred will give 600 .

Given,

Rounding 636 to nearest ten and hundred .

Here,

The number in the tens place is 3.  The number after that is 6 which is greater than 5 so you round up.  Therefore 636 rounded to the nearest tens place is 640.

The number in the hundreds is 6, the next number is 3 and since it is less than 5, you keep it at the same.  636 rounded to the nearest hundred place is 600.

Know more about rounding off ,

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The number in the tens place is 3.  The number after that is 6 which is greater than 5 so you round up.  Therefore 636 rounded to the nearest tens place is 640. 
The number in the hundreds is 6, the next number is 3 and since it is less than 5, you keep it at the same.  636 rounded to the nearest tens is 600.

What is 3/4 of 2 3/4

Answers

Answer:

The answer of your question is 2.0625

There are 26 students in an algebra class. The number of girls in the class is one less than twice the number of boys. How many boys are in the class.

Answers

g = girls in class

b= boys in class

g = 2b-1

girls + boys =26

g+b=26

substitute g = 2b-1

2b-1 +b =26

combine like terms

3b-1 =26

add 1 to each side

3b -1+1 = 26+1

3b = 27

divide each side by 3

3b/3 = 27/3

b = 9

There are 9 boys

Ho do you get the Surface Area of this shape?

Answers

This solid object contains 8 sides.

The side that is facing you has a surface area:

64f{ t }^( 2 )+84f{ t }^( 2 )=148f{ t }^( 2 )

The side exactly opposite this one has the same surface area - 2 sides with this surface area in total.

The bottom side has a surface area:

84f{ t }^( 2 )

The side to your right has a surface area:

84f{ t }^( 2 )

The side to your left has a surface area:

48f{ t }^( 2 )

The side to your top left has a surface area:

48f{ t }^( 2 )

The side beside the side to the top left has a surface area:

36f{ t }^( 2 )

The side at the very top has a surface area:

36f{ t }^( 2 )

Combined, the surface area is:

S=2\cdot 148f{ t }^( 2 )+2\cdot 84f{ t }^( 2 )+2\cdot 48f{ t }^( 2 )+2\cdot 36f{ t }^( 2 )

\n \n =296f{ t }^( 2 )+168f{ t }^( 2 )+96f{ t }^( 2 )+72f{ t }^( 2 )\n \n =632f{ t }^( 2 )

Therefore the answer is: C

Really need help on this problem

Answers

The answer would be C.

-3x +y = 5

You would add 3x to both sides to get the equation of a liney = 3x + 5

What metric unit would best measure the width of a textbook

Answers

Millimeters (mL) would be enough to measure the width of a textbook