An equilateral triangle has an apothem of 5 cm. Find the perimeter of the triangle to the nearest centimeter.

Answers

Answer 1
Answer: The apothem is the distance from the center to the midpoint of one of the sides of a regular polygon.  You can make a right triangle with the apothem, the line from the midpoint to the corner and the line from the center to the corner.  An equilateral triangle has 60 degree angles (180/3).  The right triangle has half of one of those angles so 30 degrees.  Now we have a 30-60-90 triangle where the short leg is 5cm.  The long leg, which is also half of one side of the triangle is thus 5√(3).  A whole side of the triangle is 10√(3).  Multiply that by 3 to get the perimeter of 30√(3).

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Are the equations m 3 = −5 and m = −2 equivalent? explain.

Answers

m = {-0.5, 0.5}that is the plot

The width of a singles tennis court is 27 feet. this is 1 foot more than 1/3 of the lenght. what is the length of the court

Answers

w = 27
1 + 1/3L = w
1 + 1/3L = 27
1/3L = 26
L = 78

i am a mathematics teacher. if anything to ask please pm me

10,infinity
Interval notation-
Inequality notation-

Answers

Answer:

hi

Step-by-step explanation:

Which equation in slope-intercept form, passes through the points (2, 15) and (5, 21)?

Answers

Answer:

y = 2x + 11

Step-by-step explanation:

Slope-intercept form (y=mx+b) of linear equations highlights the slope (m) and the y-intercept (b) of a line.

Slope = m = rise/run = (y2-y1)/(x2-x1) = (15-21)/(2-5) = -6/-3 = 2

substitute 2 back into the equation.

y = mx + b

y = 2x + b

use one of the provided points to solve for b.

y = 2x + b

15 = 2(2) + b

15 = 4 + b

11 = b

y = 2x + 11

The numbers on a football field indicate 10 yard increments. You walk around the perimeter of a football field between the pylons. You walk a distance of 306 and 2/3 yards. Find the area and perimeter of the indicated regions. Write your answers as mixed numbers, if necessary. One end zone

Answers

Answer: 126.67 is the perimeter walked

Step-by-step explanation:

Given data:

Distance walked on the field = 306 2/3 yards.

Increments on the field = 10 yards.

Solution:

We know a pitch has 4 sides let make it A, B,C,D = 306.67yards.

each has an increment of 10

= 10 x 10 + 10 x 10 = 200

Therefore

= 306.67 yards – 200

= 106.67 yards.

For both end zones Perimeter

= 106.67 + 10 + 10

= 126.67 yards

Final answer:

The area of the end zone is 6400 square yards and the perimeter is 326 and 2/3 yards.

Explanation:

To find the area and perimeter of the end zone of a football field, we need to know the dimensions of the end zone. If the end zone has a width of 53 and 1/3 yards, we multiply the width by the length of the field, which is 120 yards, to find the area. So the area of the end zone is (53 and 1/3) x 120 = 6400 square yards. The perimeter is found by adding the dimensions together, so the perimeter of the end zone is (2 x 53 and 1/3) + (2 x 120) = 326 and 2/3 yards.

Learn more about Area and perimeter of a football field end zone here:

brainly.com/question/13940257

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In the equation x^2-6x+8=0 what are the solutions for x

Answers

Hello,

x²-6x+8=0
==>x²-2x-4x+8=0
==>x(x-2)-4(x-2)=0
==>(x-2)(x-4)=0
==>x=2 or x=4.
(x= -4,-2) if you want to know how check out this video (YouTube.com/watch?v=E7bnvVQe_No)