Malena swam 918 meters in 3 days.If she swam the same distance each day . How far did Melanie swim in one day?
Answers
Answer:
306
Hope this helped, have a good rest of your day!!:D
Step-by-step explanation:
If I did it right, you divide 918 by 3 and you would get 603... if this is what ypu were looking for.
Final answer:
If Malena swam 918 meters over 3 days with the same distance each day, she swam 306 meters per day.
Explanation:
The solution to this problem involves simple division. The total distance swam by Malena, which is 918 meters, will be divided by the amount of days she spent swimming, which in this case, is 3 days.
So, 918 meters ÷ 3 days = 306 meters/day.
Therefore, "Malena swam 306 meters each day if the distance was distributed equally among the 3 days".
Learn more about Division here:
#SPJ3
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Which number is between 0.6 and 7/9A 23/27B 31/45C 14/27D 1/3
Answers
.3(24.40a + 14.50c)
24.40 = cost of adult ticket
14.50 = cost of child ticket
a = # of adult tickets sold
c = # of child tickets sold
.3 * 24.40a + .3 * 14.50c
answer: 7.32a + 4.35c
Answers
Answer:
Step-by-step explanation:
Probability =
Given : A number cube is tossed and one card is randomly drawn.
Total outcomes for cube = 6
Total outcomes fro cards = 5
Number of yellow cards = 3
Event 1 : drawing 3 on cube .
Event 2 : drawing a yellow card .
Since both events are independent then probability of getting 3 on cube and a yellow card is
i.e.
Hence, P(3, yellow)=
Answers
Answer:
Note from question, Let K be any integer. Integer = 1
θ = πk
θ = 3.142 * 1
θ = 3.142 in three decimal places
θ = sin⁻¹ (2/3) + 2kπ
θ = sin⁻¹0.667 + 2*1*3.142
θ = 0.718 + 6.284
θ = 7.002 in three decimal places
∴ 7.002 , 3.142
Step-by-step explanation:
Considering the equation
3 tan(θ) sin(θ) − 2 tan(θ) = 0
The objective is to solve the equation.
First solve the equation in one period.
3 tan(θ) sin(θ) − 2 tan(θ) = 0
( 3sinθ − 2 ) tanθ = 0
Therefore, 3sinθ − 2 = 0 also tanθ = 0
=> sinθ = 2/3 , tanθ = 0
Pick the right equation.
tanθ = 0
θ = tan⁻¹ 0
θ = 0
Using the unit circle, the period of tangent functions is π
Then the general solution of the equation is θ = 0 + πk ==> θ = πk
Pick the left equation.
3sinθ − 2 = 0
3sinθ = 2
sinθ = 2/3
θ = sin⁻¹ (2/3)
As the sine function has period 2π
Then the general solution is θ = sin⁻¹ (2/3) + 2kπ
Answers
-- All three sides of a scalene triangle have different lengths.
So 'x' can't be 15 and it can't be 25.
-- 'x' must be 10 or more in order to reach between the ends
of the 25 and the 15.
-- 'x' must be less than 40 in order for the 25 and the 15 to reach
between its ends.
So the value of 'x' must satisfy these conditions:
0 < x < 15
15 < x < 25
25 < x < 40
Any number that satisfies these conditions is an acceptable value for 'x'.
This triangle is really flat. So much so that you could put it on a number line.
It literally cannot get any flatter, and the largest side literally cannot get any bigger.
Well, the smaller two sides would add up to equal the third.
From this we have realized something: The largest side of any triangle cannot be larger than the sum of the other two.
Let's think back to our problem.
What are the possibilities for
If
If
15 and
Since it's a scalene triangle, x cannot be 15 or 25 either, so add that too.
Answers
all you're doing is counting how many times you move the decimal