Where does potential energy come from

Answers

Answer 1

Answer: If earth were to every pull back on that object, this is where its kinetic energy will come from. Regarding some other planet pulling it, note that there is currently potential energy stored in the object(when it is onearth), in the other planet's gravitational field.

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A basic observation of a star is how bright it appears. This brightness is known as the star'sA. luminosity.B. absent magnitude.C. apparent magnitude.D. absolute magnitude.
a tuna fish is streamlined to reduce friction which describes the type of of friction the fish must overcome
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The mass of cart 1 was 1.10kg and mass of cart 2 is what's being solved for. They were next to each other and a spring was activated and the two carts moved away from each other and produced these readings. Cart 1= v1: .75 m/s and Cart 2= v2: .34m/s. What's the mass of cart 2

Answers

m1v1 + m2v2 = m1v1i + m2v2i
fill it in m1 = mass 1
m2 = mass 2
v1 = velocity 1
v2 = velocity 2

In a closed system, glider A with a mass of 0.40 kg and a speed of 2.00 m/s collides with glider B at rest with a mass of 1.20 kg. The two interlock and move off. What speed are they moving at?

Answers

The speed are they moving at will be 0.5 m/sec.Law of conservation of momentum is applied.

What is the law of conservation of momentum?

According to the law of conservation of momentum, the momentum of the body before the collision is always equal to the momentum of the body after the collision.

The given data in the problem is;

(m₁) is the mass of 1st gilder= 0.40 kg

(u₁) is the initial velocity = 2 m/s

(m₂) is the mass of 2nd gilder = 1.20 kg

(u₂) is the initial velocity of 2nd gilder = 0 m/s

(v) is the velocity after collision =.?

According to the law of conservation of momentum;

Momentum before collision =Momentum after collision

$\rm m_1u_1 + m_2u_2 = v(m_1 + m_2)\n\n(0.40* 0.25) + (1.2 * 0) = v * (0.40+1.20) \n\n 125 + 0 = v * (1250) * 125 \n\n \rm v= (0.8)/(1.6) \n\n \rm v= 0.5 \ m/sec$

Hence, the speed are they moving at will be 0.5 m/sec

To learn more about the law of conservation of momentum refer;

brainly.com/question/1113396

#SPJ2

Conservation of momentum.
m1*u1 + m2*u2 =m1*v1 + m2*v2
here u2=0 body at rest, v1=v2=v both interlock and move together
0..4*2+1.2*0 = 0.4*v+1.2*v
v= 0.8/1.6 = 0.5 m/sec

If the absolute temperature of a gas is 600 K, the temperature in degrees Celsius isa. 273°C.
c. 705°C.
b. 327°C.
d. 873°C.

Answers

Kelvin is a base unit of temperaturescale from SI that defines as zero degree Kelvin (absolute zero). The absolutezero is a hypothetical statement that all molecular movement stops becausethere is no transient of energy for the molecules to move. When convertingtemperature in degree Celsius to Kelvin, add 273. You are given 600K and youare asked to find it in degrees Celsius.

T(K) = T(C) + 273
600 K = T(C) + 273
T(C) = 600 – 273
T(C) = 327 °C
The answer is letter B.

Answer:

Explanation:327

What terms are needed to completely describe velocity?

Answers

In order to completely describe a velocity,
you need a speed and a direction.

Which motion causes the apparent rising and setting of the moon each day as seen from a local location in Kansas

Answers

The apparent daily rising and setting of EVERY natural object
in the sky, as seen from virtually anywhere on Earth ... the sun,
every other star, the moon, every planet, comet, asteroid, galaxy,
etc. ... is the result of the daily rotation of the Earth itself.

Roughly every 24 hours, your eyes get turned in a complete circle.
To keep watching any one thing in the sky, the direction you have
to look keeps turning. In order to stare at the moon, you need to turn
your eyes, and eventually turn your head. You don't feel the Earth
turning, so your brain decides that the Moon must be moving across
the sky.

The Earth's revolution in its orbit has nothing to do with the apparent
daily rising and setting of anything.

The eye of the Atlantic giant squid has a diameter of 3.50 × 10^2 mm. If the eyeis viewed in a concave mirror with a radius of curvature equal to the diameter
of the eye and the eye is 0.800 × 10^3 mm from the mirror, how far is the image
from the mirror? What is the size of the image? Is the image real or virtual?