The metricsystem was first put into practice in 1799, during the French Revolution, when the existing system of measures became impractical for trade and was supplanted by a decimal system based on the kilogram and the meter.
During the FrenchRevolution, the existing system of measures became impractical for trade and was replaced by a decimalsystem based on the kilogram and the meter, and the metricsystem was born.
In 1793, the meter was defined as one ten-millionth of the distance from the equator to the NorthPole along a great circle, implying that the Earth's circumference is approximately 40000 km.
The meter was redefined in 1799 in terms of a prototype meter bar.
The meter was introduced as a new unit of length, defined as one ten-millionth of the shortestdistance between the NorthPole and the Equator passing through Paris, assuming an Earth flattening of 1/334.
Thus, this is the history of the metric system as it applies to the meter.
For more details regarding metric system, visit:
#SPJ2
Answer and explanation;
In 1670 Gabriel Mouton, Vicar of St. Paul’s Church and an astronomer proposed the swing length of a pendulum with a frequency of one beat per second as the unit of length.
In 1791 the Commission of the French Academy of Sciences proposed the name meter to the unit of length. It would equal one tens-millionth of the distance from the North Pole to the equator along the meridian through Paris.It is realistically represented by the distance between two marks on an iron bar kept in Paris.
In 1889 the 1st General Conference on Weights and Measures define the meter as the distance between two lines on a standard bar that made of an alloy of 90%platinum with 10%iridium.
In 1960 the meter was redefined as 1650763.73 wavelengths of orange-red light, in a vacuum, produced by burning the element krypton (Kr-86).
In 1984 the Geneva Conference on Weights and Measures has defined the meter as the distance light travels, in a vacuum, in 1299792458⁄ seconds with time measured by a cesium-133 atomic clock which emits pulses of radiation at very rapid, regular intervals.
Answer:
b
Explanation:
defenettly right
Answer:
5.03×10¯⁷ N
Explanation:
From the question given above, the following data were obtained:
Mass of the person (M₁) = 55 Kg
Mass of the car (M₂) = 1234 Kg
Distance apart (r) = 3 m
Gravitational constant (G) = 6.673×10¯¹¹ Nm²/Kg²
Force (F) =?
The force between the person and his car can be obtained as follow:
F = GM₁M₂ / r²
F = 6.673×10¯¹¹ × 55 × 1234 / 3²
F = 6.673×10¯¹¹ × 67870/ 9
F = 5.03×10¯⁷ N
Thus, the force between the person and his car is 5.03×10¯⁷ N