12x²-7x+10=0 by quadratic formula

Answers

Answer 1

Answer: Photo attached with the working out.

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F (a)=2a^2-16a+32 For which 'a' is this equation 0?
Choose the equation below that represents the line that passes through the point (7, −2) and has a slope of −3.y − 2 = −3(x + 7)y + 7 = −3(x − 2)y + 2 = −3(x − 7)y − 7 = −3(x + 2)

A die is rolled 200 times with the following results.Outcome
1
2
3
4
5
6
Frequency
32
36
44
20
30
38
What is the experimental probability of rolling the given result?
a.
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c.
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b.
0.34
d.
0.44

Answers

Final answer:

The experimental probability of rolling the given results are: a. 0.16, b. 0.18, c. 0.22, d. 0.1. The correct answer is b. 0.18.

Explanation:

To find the experimental probability of rolling a given result, divide the frequency of that result by the total number of rolls. In this case, the frequency of rolling a 1 is 32, and the total number of rolls is 200. So the experimental probability of rolling a 1 is 32/200 = 0.16. Repeat this process for the other results:

Experimental probability of rolling a 2: 36/200 = 0.18
Experimental probability of rolling a 3: 44/200 = 0.22
Experimental probability of rolling a 4: 20/200 = 0.1
Experimental probability of rolling a 5: 30/200 = 0.15
Experimental probability of rolling a 6: 38/200 = 0.19

Based on these calculations, the experimental probability of rolling the given results are:

a. 0.16
b. 0.18
c. 0.22
d. 0.1

Therefore, the correct answer is b. 0.18.

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Answer: D) 0.44

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Explanation:

Add up all the frequencies that correspond to outcomes that are more than 3

So we'll add up the last three frequencies (since they correspond to outcomes of 4, 5 and 6 all of which are greater than 3) to get 20+30+38 = 88

We have 88 occurrences of rolling either a 4, a 5 or a 6. This is out of 200 rolls total.

The empirical (or experimental) probability of getting more than 3 on the die is 88/200 = 0.44

Express 59/100 as a decimal

Answers

59/100=.59 when you are dividing by hundred whatever you're dividing by will be the same answer in decimal form

I did 70 jumping jacks in 1 minute.Which is the dependent variable? Which is the independent variable?

Write an equation that represents the relationship between the time you spent doing the activity and the amount of the activity you completed.

Answers

Answer:

in jh ynhtym

hunt ghb JBL iggmmjuu ki ju nu j

(x^-2/y^-3)^2 / (y/x^2)^-3

Answers

$( (( x^(-2) )/( y^(-3) ))^2 )/( ((y)/( x^(2) ))^(-3) ) = ( (( x^(-4) )/( y^(-6) )) )/( (( y^(-3) )/( x^(-6) )) )= ( x^(-4)* x^(-6) )/( y^(-3)* y^(-6) ) = ( x^(-10) )/( y^(-9) )$

(x-²/ y-³)² = (x-²/y-³)(x-²/y-³) = (y/ x²)(y/ x²) = (y²/ x^4) = y² · x^4 = 1
(y/ x²)-³ (y/x²)(y/x²) (x²/y³)(x²/y³) (x^4/ y^6) x^4 · y^6 y^4

A student has 174 cm of ribbon for making bows. Each bow is made with 20 cm of ribbon. The student wants to make as many bows as possible. How many bows can the student make? How many centimeters of ribbon will be left over?

Answers

Step-by-step explanation:

To find how many bows can be made take the 174 and divide it by 20

You get 8.7. The student can make 8 full bows. Now take 20 and times it by eight, this is how much ribbon in total the student used in bows. 160. Now 174-160. This makes 14.

The student can make 8 full bows with 14cm of ribbon left over.

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