Perform the indicated operation. Answers.a. 10ab/3

b. 3/10ab

c. 10/3ab
Perform the indicated operation. Answers. a. 10ab/3 b. 3/10ab c. - 1

Answers

Answer 1
Answer: c.
(10)/(3ab)

Related Questions

Will mark brainliest. The top question is the one I need answers. Please help thank you.
Please help me solve this question:)​
Name1. Emerson is starting a new business. Product Acosts her $26.50. She decides to mark theproduct up 30%. How will Emerson charge forProduct A
Round 56,291.8 to the nearest thousand
Which ordered pairs are solutions to the equation? y = 3x + 1A.(6, 19) and (0, 0)B.(6, 18) and (0, 1)C.(6, 19) and (0, 1)D.(19, 6) and (0, 1)

In the figure, the measure of angle 7 is 57°. What is the measure of angle 8?

Answers

Answer: The measure of angle 8 is  123° .

Step-by-step explanation:

Since we have given that

m∠7 = 57°

we have two lines intersecting each other at one point forming angles ∠7, ∠8, ∠5, ∠6.

So, Relation between ∠7 and ∠8 is linear pair.

And we know that ,

\angle 7+\angle 8=180\textdegree\n\n57\textdegree+\angle 8=180\textdegree\n\n\angle 8=180\textdegree-57\textdegree\n\n\angle 8=123\textdegree

Hence, the measure of angle 8 is  123° .

Angle (6) + Angle (7) = 180

Angle (6) + 57 = 180

Angle (6) = 180 - 57

Angle (6) = 123

------------

Angle (6) = Angle (8)

-----------

Therefore:

Angle (8) = 123 degrees

If B1 = 3 m and B2 = 4m and the area is 7 m squared, what is the height?

Answers

the height is 1, because it's A=(b1 + b2)*h, the equation is this now 7=3 + 4)*h, you add 3 + 4 then that will give you 7, so now it should look like this 7=7*h, you do a fraction line under the 7 and 7*h each, and put a 7 as the denominator, so it kind of looks like this now 7 = 7*h
                                                                      __   __
                                                                        7    7      then you cancel the 7*h which leaves you to just h, so 7 divided by 7 will give you 1 so it looks like 1=h, PHEW

What is 8(x+12)=2(5x+9)

Answers

8(x+12)=2(5x+9)
8x+96=10x+18
2x+18=96
2x=78
x=39
8(x+12)=8x+96
2(5x+9)= 10x+18
8x+96=10x+18
     -18        -18
---------------------
  8x+78= 10x
 - 8x       -8x
-----------------
78=2x
78÷2=36

HURRY PLS!!!!!!!!Let p: A car has automatic windows. Let q: A car has automatic seats. p v q is true for a total of how many cars? 40 54 66 80

Answers

Answer:

The answer is D on edgen.

Step-by-step explanation:

D. 80

(all you do is add 40, 14 and 26 from the graph)

Answer:it’s 80

Step-by-step explanation:

edg 2022 frfr

0.34 x 9 = ? (Help me, please!)

Answers

0.34 x 9 = 3.06 so 3.06 is your answer
If you multiply .34 times 9 your answer will be 3.06

What is the surface are of the square

Answers

Answer: Thats not a square.

Step-by-step explanation:

Answer:

49cm²

Step-by-step explanation:

The base of the triagular prism is 7 *7 so 49

Other Questions
Plz help, I need answers to these questions ASAP, would appreciate a short step-by-step explanation with each! WILL MARK BRAINLIEST!!!You’ve been given $500.00 for your fencing. So first we are going to make as big of a rectangular field as we can with the money that we have for the fencing to surround it. The cost of premium fencing (only the best for your farm, of course) is $11.41 per metre. So with that, and the following equations:A=l*wP=2l+2wWhere A is the area, P is the perimeter, l is the length, and w is the width of a rectangle, we can find the maximum area that we can have for this field.Perimeter of fence:Area of farm:Let’s say we have access to planting 2 different crops, Watermelons and Grapes. We can find the revenue of a crop by the equation:R = (p0 + px)(n0 - nx)Where R is the revenue, p0 is the starting price, n0 is the amount sold at the starting price, p is the price increase, n is the decrease in the amount sold per price increase, and x is the number of price increases.Crop A: Watermelons have a starting price of $12.00 per m2 of area sold. At this price, you can sell 45 m2 worth. For every $2.00 increase, you will sell 1 m2 less. So the first task is to figure out how to put these values into the equation above and turn it into a quadratic function. Then you will need to find the value of x to make the revenue as large as possible. Once you know x, the number of price increases, you can then find what you should price your Watermelons per m2.Equation: R =Number of price increases: x =Price of Watermelon per m^2 =Okay, now we can do the same thing with the grapes, just to give you that extra practice with quadratic functions. The starting price of grapes per m² is $8.00, at which you can sell 60 m² worth. For every $3.00 increase in price, you sell 3 m² less. So use the same method you just used to find the price of grapes per m² of area to maximize revenue.Equation: R =Number of price increases: x =Price of grape per m^2 =Okay, so now, all in all, we have built our farm and found what to price each of our crops at. Now let’s find what amount of each crop to grow and find our profits. Getting right into it, we have the following cost equations:CW = $20.00 * W + $50.00CG = $10.00 * G + $40.00Where CW is the total cost of planting and growing Watermelons, CG is the total cost of planting and growing Grapes, W is the area of Watermelons planted, and G is the area of Grapes planted. Now that we know our cost, we can finally find our profits. Profit is equal to the price per unit area, multiplied by the area sold, subtracted by the total cost planting and growing them, or, Profit = Price * Area - Cost. But at this point, we still don’t know the area of each crop in our field. But we do know a couple of things to figure it out. We know the total area of our farm, found in the first part. Which we can say is, Area = G + W And we were also only given $1590 to plant the crops. So, $1590.00= CW+CG I’ll help you simplify this a bit:$1590.00=$20.00*W+$50.00+$10.00*G+$40.00 $1590.00=$20.00*W+$10.00*G+$90.00So now we have enough information to solve for the areas of Watermelons and Grapes in your field. Here’s some room to do that. Hint: Use either substitution or graph the two equations to find an intersection.Area of watermelon to plant:Area of grapes to pant:Profit of the crops: