Answer:
(x^2+8) ( y+4)
Step-by-step explanation:
x^2y + 8y+ 4x^2 +32
Splitting into two groups
x^2y + 8y+ 4x^2 +32
Factor y out of the first group and 4 out of the second group
y( x^2+8) + 4(x^2+8)
Factor out (x^2+8)
(x^2+8) ( y+4)
Answer:
(x^2+4)(y+3)
Step-by-step explanation:
x^2y+4y+3x^2+12
factor by grouping
=x^2y+4y + 3x^2+12
left. right
take common in left y and in right 3
=y(x^2+4) + 3(x^2+4)
now common term is (x^2+4)
=(x^2+4) (y+3) answer
When you substitute 0 for the exponent x, the expression simplifies to a times 1, which is just a. This is because any number to the 0 power equals 1. Since the initial value is the value of the function for an input of 0, the initial value for any function of this form will always be the value of a.
Answer:Sample Response: When you substitute 0 for the exponent x, the expression simplifies to a times 1, which is just a. This is because any number to the 0 power equals 1. Since the initial value is the value of the function for an input of 0, the initial value for any function of this form will always be the value of a.
Step-by-step explanation:
A. 194.2
B. 19.42
C. 1942
D. 19,420
Answer:
D
Step-by-step explanation:
Answer:
a
Step-by-step explanation: