374 × 510

What are the partial products Lucas will need to solve the problem?

Answers

Answer 1

Answer: The partial products that Lucas would need to solve this problem would be 3,740 and 187,000 if you are multiplying 374 on the top column and 510 on the bottom column. Or, the partial products Lucas would need is 2,040 and 35,700 and 153,000. Both partial products combination added together would be 190,740.

Answer 2

Answer:

Answer:

3,740 and 187,000

Step-by-step explanation:

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Drag and drop the correct number to complete the equation.

Answers

Answer:

20/33

Step-by-step explanation:

because math says so

Convert each mixed number to improper fraction form

3 & 1/3 = 3 + 1/3

3 & 1/3 = 9/3 + 1/3

3 & 1/3 = 10/3

5 & 1/2 = 5 + 1/2

5 & 1/2 = 10/2 + 1/2

5 & 1/2 = 11/2

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Then use those two improper fractions to divide. You take the reciprocal of the second fraction and then multiply.

(3 & 1/3) divided by (5 & 1/2) = (10/3) divided by (11/2)

(3 & 1/3) divided by (5 & 1/2) = (10/3) * (2/11)

(3 & 1/3) divided by (5 & 1/2) = (10*2)/(3*11)

(3 & 1/3) divided by (5 & 1/2) = 20/33

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Answer: 20/33

Does it matter what interval you use when you find the rate of change of a proportional relationship

Answers

Proportions are the comparison of two equal ratios. Therefore, proportional relationships are relationships between two equal ratios. So yes, it does matter.. Interval: all the numbers between two given numbers.

Plot the zeros of the polynomial y = x4 + 3x3 − 27x2 + 13x + 42

Answers

Answer:

See explanation

Step-by-step explanation:

Consider the polynomial $y=x^4+3x^3-27x^2+13x+42$ 4th power polynomial function has at most 4 zeros.

Integer zeros can be only among the divisors of 42:

$\pm1, \ \pm 2,\ \pm 3,\ \pm 6,\ \pm 7,\ \pm 14,\ \pm 21,\ \pm 42$

Check them:

$y(1)=1^4+3\cdot 1^3-27\cdot 1^2+13\cdot 1+42=1+3-27+13+42=32\neq 0\n \ny(-1)=(-1)^4+3\cdot (-1)^3-27\cdot (-1)^2+13\cdot (-1)+42=1-3-27-13+42=0\n \ny(2)=2^4+3\cdot 2^3-27\cdot 2^2+13\cdot 2+42=16+24-108+26+42=0\n \ny(3)=3^4+3\cdot 3^3-27\cdot 3^2+13\cdot 3+42=81+81-243+39+42= 0\n \ny(-7)=(-7)^4+3\cdot (-7)^3-27\cdot (-7)^2+13\cdot (-7)+42=2,401-1,029-1,323-91+42= 0$

Thus,

$y=(x+7)(x+1)(x-2)(x-3)$

Zeros are plotted in attached diagram.

Answer:

The remainder is 0, so -1 is a zero of the polynomial and x + 1 is another factor: (x − 2)(x + 1)(x2 + 4x − 21). Now factor the remaining polynomial using normal means. The fully factored form is (x − 2)(x + 1)(x + 7)(x − 3), so the zeros of the polynomial are x = 2, -1, -7 and 3.

Step-by-step explanation:

What is the slope of the line x=-6!?
What about y=6
Please explain :)

Answers

So,

These are actually special cases.
x = -6

No matter what value we substitute for y, x will always be -6.
These are some solutions to it:
(-6, 0)
(-6, -2)
(-6, 50)

Now, we know that:
$slope(m) = (rise)/(run)$

But the run is zero, because the line is vertical. And dividing by zero is not allowed. Therefore, the slope of the line x = -6 is undefined.

y = 6

This is basically the same type as the previous one, with one exception.

Some solutions:
(0, 6)
(-47, 6)
(59, 6)

No matter what value we substitute for x, y will always be 6.

Remembering what the slope is equal to, we quickly see that since the rise is zero, and the denominator is infinite, we can conclude that the slope is zero.

This is super simple. :)
If it is asking for a x=a it will always be 0 because there is no y intercept. It is a horizontal line.
For y=6 is undefined because it is a straight verticle line. An easy way to remember is if it is y or x = something with just 1 number and no coefficents on that number it will be x=0 or y=undefined. Also try to picture how it would graph and it might help. :)

Lorna has 60$ and her sister has 120$ Lorna saves 7$ Per week and solution represent the number of weeks w it will take for girls to have the same amount of money