I will award brainliest!!In the given figure, the reflex angle ∠DOB has measure of 3.5y while the measure of ∠AOD is y. Find the measure of the non-reflex ∠DOB in degrees.
i will award brainliest!! In the given figure, the reflex - 1

Answers

Answer 1
Answer:

Answer:

In the given figure:

The reflex angle \angle DOB=3y and \angle AOD = y

\angle COB = \angle AOD = y  [By vertical angle theorem]

From the given we can say that:

\angle AOC and \angle COB are supplementary angles.

Supplementary angles states that the two measure are add up to 180 degree.

\angle AOC +\angle COB = 180^(\circ)          .....[1]

then; the reflex angle DOB is:

\angle DOB = \angle AOD + \angle AOC + \angle COB

Substitute the given values we get;

3.5y=y+180^(\circ)

Subtract y from both sides we get;

2.5 y = 180^(\circ)

Divide both sides by 2.5 we get;

y = 72^(\circ)

\angle DOB = 3y = 3.5(72) =252^(\circ)

We have to find the non reflex \angle DOB

Non reflex angle DOB is;

\angle DOB = 360^(\circ)-252^(\circ) = 108^(\circ)

Therefore, the non-reflex angle DOB is 108 degree.


     

Answer 2
Answer:

Answer: 252 degrees

Step-by-step explanation: so we know that a half circle is 180.


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PLEASE HELP I GIVE THANKS

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Option B) is correct because the mode is 5. A mode is the most often occurring number in a list of numbers. The list of numbers is: 5, 1, 9, 5, 6, 9, 5, and 12.

What is 10 to the 40 power divided by 38 time 4 minus 300 and then add 5

Answers

I think this is a troll, but doing it anyway:

(((   10^40   )/ 38  )*4) -300 + 5 , this would be so much easier if there wasn't a power to 40, now we have this huge as number.

The answer is
, 1.0526316e + 39 , I don't know what the e means, sorry, but you asked a silly question so you get a silly answer

What is the lateral area of the rectangular prism? 

Assume the prism is resting on its base.

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lateral\ area\ is:\n2\ rectangles\ 5in*15in\ and\ 2\ rectangles\ 4in*15in\n\nlateral\ area\ of\ the\ rectangular\ prism:\n\n2\cdot5\cdot15+2\cdot4\cdot15=150+120=270\ (in^2)\n\nAnswer:B

An observer spots a plane flying at a 42 degree angle to his horizontal line of sight. If the plane is flying at an altitude of 15,000 ft, what is the distance (x) from the plane (P) to the observer (O)

Answers

This seems like a high school question. I will use trigonometry.

The three points (P, O, and the point on the ground directly below P [call it G]) form a right triangle. The 42-degree angle is opposite PG, the altitude of the plane. Since we are told to find x, which is PO, we can use the definition of the sine function, which is opposite divided by hypotenuse.

sin(42^o)=(opp)/(hyp)=(15,000ft)/(x)


Solving for x,

x=(15,000ft)/(sin42^o)=(15,000ft)/(.66913)=22420\ ft


This makes sense because the hypotenuse must be longer than either of the legs.

Describe two prisms that each have 2400 cubic centimeters. Draw each

Answers


V = 12 * 40/2 * 10 = 2400 


V = 24 * 10 * 10 = 2400

14c^3d^2-21c^2d^3/14cd

Answers

14c³d²-21c²d³/14cd

= (196c^4d³-21c²d³)/ 14cd

= (196c³d²-21cd²)/14

= (28c³d²-3cd²)/2


I hope that's help !