MATHEMATICS MIDDLE SCHOOL

Suppose that g (x) varies inversely with x and g (x)=0.2 when x = 0.1.What is g (x) when x = 1.6?

0.0125
0.032
0.02
0.06

Answers

Answer 1

Answer:

Answer : 0.0125

Suppose that g (x) varies inversely with x and g (x)=0.2 when x = 0.1.

If x varies inversely with y then y=k/x

Where k is constant of proportionality

g (x) varies inversely with x , so $g(x) = (k)/(x)$

g (x)=0.2 when x = 0.1

Plug in the values and solve for k

$g(x) = (k)/(x)$

$0.2 = (k)/(0.1)$

Multiply 0.1 on both sides

0.02 = k

so $g(x) = (0.02)/(x)$

Now we need to find g(x) when x= 1.6

Plug in 1.6 for x and find out g(x) in the above equation

$g(x) = (0.02)/(1.6)$

g(x)= 0.0125

Answer 2

Answer:

Answer:

A. 0.0125

Step-by-step explanation:

0.2*0.1= 0.02

.02/1.6 = 0.0125

Took the test and got it correct

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