MATHEMATICS HIGH SCHOOL

PLEASE HELP ME FIGURE THIS OUT 1..

Answers

Answer 1

Answer:

Answer: π/6

Step-by-step explanation:

sec θ = $(2)/(√(3))$

sec = $(1)/(cos)$

⇒ $(1)/(cos)$ = $(2)/(√(3))$

⇒ cos θ = $(√(3))/(2)$

Since it is an acute angle, then 0° > θ > 90°

Look at the Unit Circle to find that cos θ = $(√(3))/(2)$ at π/6

***********************************************************************

Answer: -300°

Step-by-step explanation:

Set up the proportion:

$(\pi )/(180) = \frac{-5\pi} {3x}$

Cross multiply and solve:

π(3x) = 180(-5π)

x = $(180(-5\pi))/(3\pi)$

x = 60(-5)

x = -300

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Factor the following expression...
x^2 - 2x - 3

Answers

Trying to factor by splitting the middle term

1.1     Factoring  x2-2x-3

The first term is,  x2  its coefficient is  1 .
The middle term is,  -2x  its coefficient is  -2 .
The last term, "the constant", is  -3

Step-1 : Multiply the coefficient of the first term by the constant   1 • -3 = -3

Step-2 : Find two factors of  -3  whose sum equals the coefficient of the middle term, which is   -2 .

-3 + 1 = -2 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above,  -3  and  1
                     x2 - 3x + 1x - 3

Step-4 : Add up the first 2 terms, pulling out like factors :
                    x • (x-3)
              Add up the last 2 terms, pulling out common factors :
                     1 • (x-3)
Step-5 : Add up the four terms of step 4 :
                    (x+1)  •  (x-3)
             Which is the desired factorization

Final result : (x + 1) • (x - 3)

hope this helps hope i am brainliest i need it

Terri's teacher gives her the equation 3(5)^x=127-2x, and tells her that she will not know how to solve it algebraically. Explain how Terri could use a graph to solve the equation, find the value of x to the nearest tenth

Answers

$f(x)=3\cdot5^x\ \ \ and\ \ \ g(x)=127-2x\n\nf(x)=g(x)\ \ \ \Leftrightarrow\ \ \ x\approx2.3043\n\nthe\ graph\ in\ annex$

HELP ME PLEASE! 30 POINTS

Answers

Answer:

C=14

Step-by-step explanation:

To find the minimum value, graph each of the inequalities. After graphing each inequality, test a point and shade the region that satisfies the inequality. Once all inequalities have been shaded, find the region where they all overlap. The region will be bounded by intersection points. Test each of these points into C=x+3y. The least value for C is the minimum.

(14,0) (0,17.5) (3.08,3.64)

C=14+3(0) C=0+3(17.5) C=3.08 + 3(3.64)

C=14 C=52.5 C=14

Hello there,

Answer: C=14

The table below shows the price of rolls at a bakery. A baker’s dozen includes 13 rolls for the price of a dozen rolls. How much money is saved by buying a baker’s dozen instead of 13 individual rolls?

Answers

it's 0.60

Have an nice nice day

On Monday, it took Helen 3 hours to do a page of science homework exercises. The next day she did the same number of exercises in 2 hours. If her average rate on Monday was pexercises per hour, what was her average rate the next day, in terms of p?

Answers

p- it is amount of exercises
average= $(exercises)/(hour)$
Monday average= $(p)/(3h)$
Tuesday average= $(p)/(2h)$
If we take into account both days and calculate average from Monday and Tuesday ( we sum 3h on Monday and 2 hours on Tuesday and p exercises on Mon and p exercises on Tuesday):
Monday and Tuesday average= $(2p)/(5)$

Which shows you how to plot (6,3) on a coordinate plane?A. Start at the origin, move 3 spaces right, and 3 spaces up.
B. Start at the origin, move 3 spaces right, and 6 spaces up.
C. Start at the origin, move 6 spaces right, and 6 spaces up.
D. Start at the origin, move 6 spaces right, and 3 spaces up.

Answers

We start with the 'x' value, which is 6.

Since it's positive we go to the right 6 times(negative will be to the left).

Now the 'y' value, 3.

Since it's positive we go 3 spaces up(negative will be down).

Therefore, our answer is D.

$Origin=>(0,0) \n \n ==>Move\:6\:spaces\:right=(6,0) \n ==>Move\:3\:spaces\:up=(6,3) \n \nThe \:correct \:answer\: is :d \n \n\framebox[1.1\width]{Godspeed!} \par$