Solve for x:

2+x=8-x

Answers

Answer 1
Answer:

2+x=8-x

add x to each side to get all the x's on one side

2+x+x = 8-x+x

2 + 2x = 8

now subtract 2 from each side to get all the numbers on the other side

2 + 2x -2 = 8-2

2x = 6

divide by 2 on each side to get x alone

2x/2 = 6/2

x=3


Answer: x=3


Answer 2
Answer:

Answer:x=3 I hope this helps you

Step-by-step explanation:

2+x=8-x

Move the variable to the left-hand side and change its sign like this

2+x+x=8

then do this

Move the constant to the right-hand side and change its sign like this

x+x=8-2

then do this

Collect like terms

Like this

2x=8-2

Subtract the numbers
2x=6

then do this

Divide both sides of the equation by 2 and you will get your answer

X=3


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What are the two consecutive number with a product of 121

Answers

x(x+1)=121 \n x^2+x-121=0 \n \Delta=485
Since \Delta is not a perfect square, the solution is not integer. So there are no consecutive numbers really.

What is base 1 of a trapezoid in which A=(48x+68) in^2, height =8, and base 2 = (9x + 12)

Answers

A=(1/2)(b1+b2)h = 

=(48x+68)in² = (1/2)( b1+(9x+12))8 


the answer is = b1= 3x+5

i hope that helped =D

Find the 30th term of the following sequence. 1, 7, 13, 19, ... 174 175 180 181.

Answers

Checking if the sequence is an arithmetic sequence 7 - 1 = 6 13 – 7 = 6 Therefore the sequence is arithmetic, with a_0 = 1 and d = 6 a_n = a_0 + (n-1)d a_30 = 1 + (29)(6) = 175 Therefore the 30th term is 175.
the rule is : 6n - 5 to find the 30th term replace n with 30 6× 30 - 5 = 175

Cube root of 8x minus 2 equals 4

Answers

Answer:

334

Step-by-step explanation:

Answer:334

Step-by-step explanation:

(sin teta + sec teta)^ + (cos teta+ cosec teta )^ = (1 + sec x cosec)^

Answers

(sin\theta+sec\theta)^2+(cos\theta+cosec\theta)^2=(1+sec\theta\ cosec\theta)^2\n\nL=sin^2\theta+2sin\theta\cdot(1)/(cos\thewta)+(1)/(cos^2\theta)+cos^2\theta+2cos\theta\cdot(1)/(sin\theta)+(1)/(sin^2\theta)\n\n=(sin^2\theta+cos^2\theta)+(2sin\theta)/(cos\theta)+(2cos\theta)/(sin\theta)+(1)/(cos^2\theta)+(1)/(sin^2\theta)

=1+(2sin^2\theta+2cos^2\theta)/(sin\theta\ cos\theta)+(sin^2\theta+cos^2\theta)/(sin^2\theta\ cos^2\theta)\n\n=1+(2(sin^2\theta+cos^2\theta))/(sin\theta\ cos\theta)+(1)/(sin^2\theta\ cos^2\theta)\n\n=1+(2)/(sin\theta\ cos\theta)+(1)/(sin^2\theta\ cos^2\theta)\n\n=1^2+2sec\theta\ cosec\theta+sec^2\theta\ cosec^2\theta\n\n=(1+sec\theta\ cosec\theta)^2=R

Find values of x and y for which ABCD must be a parallelogram. The diagram is not to scale.
a. x = 8, y = 17
b. x = 6, y = 8
c. x = 8, y = 10
d. x = 8, y = 6

Answers

The answer is d. 

3x-14 = x-2     solve for x

4y-7 = y+11    solve for y
3x-14=x+2
Add 14 to both sides.
3x=x+16
Subtract x from both sides.
2x=16
Divide by 2.
x=8

4y-7=y+11
Add 7 to both sides.
4y=y+18
Subtract y from both sides.
3y=18
Divide by 3.
y=6

The answer is d.