Donovan bought 5 1/2 kilograms of flour for $8.25 how much is the unit rate per kilogram of flour?

Answers

Answer 1
Answer:

The unit rate is given by the total amount, divided by the number of units. In this case, the amount is 8.25 dollars, and the units are 5.5 kilograms.

So, the unit cost is given by

(8.25)/(5.5) = 1.5


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Y^2+4x-6x-6y+5=0convert to standard form, find the vertex, focus, and the equation of the directrix line

Answers

I think it is :x= (Y^2)/(2)-3y+ (5)/(2).

But...not really sure



so first we group like terms
y^2+4x-6x-6y+5=0
y^2-6y-2x+5=0
so I suspect that you might have left out a x^2 but I'll try to solve it how it is

y^2-6y+5-2x=0
factor y^2-6y+5
what adds up to -6 and multiplies to get 5, -1 and -5
(y-5)(y-1)-2x=0
not sure how to procede but you could get it to this
(y-5)(y-1)=2x

A ball is thrown in the air vertically with a velocity of 112 feet per second. The height above the groundseconds after release is modeled by h(t) = -16t² + 112t + 6.
a. What height was the ball originally thrown from?
b. When will the ball reach 130 feet?
c. Will the ball ever reach 250 feet? Explain.
d. When will the ball hit the ground?

Answers

a. To find the height the ball was originally thrown from, we need to look at the equation h(t) = -16t² + 112t + 6. The initial height is represented by the constant term, which is 6. Therefore, the ball was originally thrown from a height of 6 feet.

b. To find when the ball will reach 130 feet, we need to set h(t) = 130 and solve for t. This gives us the equation -16t² + 112t + 6 = 130. Simplifying, we get -16t² + 112t - 124 = 0. Dividing by -4, we get 4t² - 28t + 31 = 0. Using the quadratic formula, we find that t ≈ 1.16 seconds or t ≈ 1.84 seconds. Therefore, the ball will reach a height of 130 feet after approximately 1.16 seconds or 1.84 seconds.

c. To determine if the ball will ever reach 250 feet, we need to look at the maximum height the ball will reach. The maximum height is given by the vertex of the parabolic equation h(t) = -16t² + 112t + 6. The t-coordinate of the vertex is given by -b/2a, where a = -16 and b = 112. Therefore, t = -112/(2*-16) = 3.5 seconds. Substituting t = 3.5 seconds into the equation, we get h(3.5) = -16(3.5)² + 112(3.5) + 6 ≈ 222. Therefore, the ball will not reach a height of 250 feet.

d. To find when the ball will hit the ground, we need to set h(t) = 0 and solve for t. This gives us the equation -16t² + 112t + 6 = 0. Dividing by 2, we get -8t² + 56t + 3 = 0. Using the quadratic formula, we find that t ≈ 0.07 seconds or t ≈ 7.93 seconds. Since the ball was thrown upwards, we can discard the negative solution. Therefore, the ball will hit the ground after approximately 7.93 seconds.

Hurry plz yeyeyeyeyeyye

Answers

Answer:

$250

Step-by-step explanation:

The triangles in the picture are congruent by which method.

Answers

Answer:  D) AAS

Explanation:

Check out the diagram below. I've marked the angles that pair up which are congruent to one another. Note the order is important. The AAS rule is different from ASA. In the diagram, the green segments are not between the red and blue angles.

Note: the blue angles are congruent by the vertical angle theorem.

Question choices
85
50
42.5
59
1.7
PLEASE HELP PLS

Answers

Answer:

42.5

Step-by-step explanation:

Multiply 50 by 0.85, which equals 42.5.

Which equation would best help solve the following problem?Maria releases a javelin 1.5 meters above the ground with an initial vertical velocity of 22 meters per second. How long will it take the javelin to hit the ground?


–4.9t^2 + 22t + 1.5 = 0

–4.9t^2 + 22t = 1.5

–4.9t^2 + 1.5t + 22 = 0

–16t^2+ 22t + 1.5 = 0

Answers

h(t) = ho +Vo.t - (g*t^2)/2

h(t) = 1.5 + 22t -4.9t^2

h(t) = 0 ⇒ -4.9t^2 + 22t + 1.5 =0. This is the first option.