Newton's 2nd Law of Motion: Force = (mass) · (acceleration)
Do I need to go any further ?
I get 575.25 Newtons .
Oh ! Look at that ! Right there at the top, it says "Using Newton's Second Law". This might have suggested to you that maybe you could solve the problem by using Newton's Second Law.
20 s.
a) What is the average acceleration of the car?
b) What distance does it travel in this time?
Explanation:
Average acceleration is defined as the rate of change of velocity to the rate of change of period. Change of velocity refers to the difference between final velocity and initial velocity. The unit of acceleration is meter/sec/sec (or) m s^2.
Avg Acceleration=(Final velocity - Initial velocity) /(Final time - Initial time)
a. To find the average acceleration of the car, (initial velocity and initial time is 0, the final velocity is 28 m/s, final time = 20 s)
Avg acceleration of the car = (28 - 0) / (20 - 0)
= 28 / 20 = 1.4 m / s^2.
b. The distance traveled is given by the product of speed and time
Distance traveled = Speed * Time
The Distance traveled by the car = 28 * 20 = 560 m.
By applying basic physics formulas, the car's average acceleration can be determined as 1.4 m/s², and the distance it travels in 20 seconds is 280 meters.
To answer this question, you'll need to apply basic physics formulas. Let's go step by step:
a) What is the average acceleration of the car?
Acceleration is defined as the rate of change of velocity per unit of time. The formula is Acceleration = (Final speed - Initial speed) / Time. Here, the initial speed is 0 (because the car is starting from rest), final speed is 28 m/s and time is 20 s.
So, Acceleration = (28 m/s - 0) / 20 s = 1.4 m/s². That's your answer for part a.
b) What distance does it travel in this time?
The distance traveled by the car can be found using the formula of linear motion: Distance = Initial speed x Time + 0.5 x Acceleration x Time². Since the car starts from rest, the initial speed is zero, and this component of the formula will be zero.
So, Distance = 0 + 0.5 x 1.4 m/s² x (20 s)² = 280 m. So, the car travels 280 meters in that time.
#SPJ3
When the speed of the bottle is 4 m/s, the KE is _____ kg m2/s2.
When the speed of the bottle is 5 m/s, the KE is _____ kg m2/s2.
When the speed of the bottle is 6 m/s, the KE is _____ kg m2/s2.
(it dident have the subject so i just picked something that deals with science)
Answer:
umm C i think
Explanation: