So here we are being asked to draw a card that isn't a heart or a queen... the amount of cards that are not hearts or queens out of a 52 card deck is 36. So that makes the probability 36/52 if we want to make that a percent then we have to change the denominator to a 100 we end up with this problem:
36/52 = x/100
There are many ways we can solve this. One way being cross multiplying, which I think is the easiest.
If our problem is a/b = c/d we multiply a and d then we multiply b and c
Plugging our original problem into that, we 36 times 100 and 52 times x. That gives us 3600 and 52x
This is now an algebraic problem.
52x=3600
First step, divide each side by 52
We get x=69.2 rounded to the nearest tenth.
So our probability is about 69/100 or 69%
Any Questions?
proability is (desired outcomes)/(total possible outcomes)
total possible outcomes is 52 cards
out of those 52 cards, how many are NOT heart or queen?
hearts is a suit, so 1/4 of the deck (or 52/4=13 cards) are not what we want
queens, there are 4 queens in a deck, but one of them is a queen of hearts. to avoid doublecount, say 3 queens
so total of 13+3=16 cards to not pick
so we have 52-16=36 cards we want to pick
probablity=36/52=18/26=9/13≈63.23%
B: 296 in^2
C: 512 in^2
D: 592 in^2
Answer:
use calculator to divide.
Step-by-step explanation:
The value of Y = 13.5
Given that,
According to the scenario, calculation of given data are as follows,
y = 27 2
y = 13.5
Learn more : brainly.com/question/19389388
Answer:
x=3 y= 13.5
Step-by-step explanation:
9/2 = y/3.....9 to 2 = y to 3
cross multiply
(2)(y) = (9)(3)
2y = 27
y = 27/2
y = 13.5