For which data sets is the median a better measure of center than the mean? Choose all answers that are correct. A. Dorian drove 56, 62, 68, 71, 104, and 507 mi on 6 consecutive days. B. Mandy entered pumpkins weighing 2, 8.5, 9.2, 9.8, and 10.1 lb in the contest at the county fair. C. The winning times in each of the 5 heats of the 400-meter dash were 1:01, 1:03, 1:03.4, and 1:04.9 min. D. The bakery shop sold 46, 51, 62, and 72 cupcakes on each of the last 2 Saturdays and Sundays.

Answers

Answer 1

Answer: Median is a better measure of center than the mean(average)

a) 56,62,68,71,104,507 ⇒ Median is a better measure. Mean is not a better measure because of the outliers.

b) 2,8.5, 9.2, 9.8, 10.1 lb ⇒ Median is a better measure.

c) Mean is a better measure. No outliers. Data set values are close with each other.

d) Mean is a better measure.

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If the population of Centerville in 1910 was 4,200 and 5,000 in 1920, assuming exponential growth, what would the population be in 2020?

a women earn $2600 per month and budget $520 per month for food .what is her monthly income is spent on food /

Answers

$2600 per month earning
$520 per month on food

Her monthly income spent on foo is about $520.

72 degrees is used in a pie chart to represent 4 people . How many people were there altogether ?

Answers

First lets find out the unit rate, the percent per person. Lets do it:-

72 ÷ 4 = 18
18% per person.

Lets find out how many people in the pie chart:-

100 ÷ 18 = 5.555.....

So, there are about 6 people in the pie chart together.

Hope I helped ya!! xD

72/4 = 18
100/18 = 5.555..
About 6 ppl.

It will take five builders 62 days to complete a particular project. At this rate, how long would the project take if there were only two builders?(SHOW WORK)

Answers

Answer:

2 builder complete work = 155 days

Step-by-step explanation:

Given:

5 builder complete work = 62 days

So,

1 builder complete work = 62 days × 5

if,

2 builder complete work = [62 days × 5] / 2

2 builder complete work = 155 days

Please help quickly

Answers

Answer:

question 1) Add 7/4 to both sides. question 2) Divide 4 by both sides. question 3) x=15

Step-by-step explanation:

Pablo folds a straw into a triangle with side lengths of 4x2 – 3 inches, 4x2 – 2 inches, and 4x2 – 1 inches. The perimeter of the triangle is 12x2 – 6 inches. If x = 1.5, what was the length of the straw before it was folded?

Answers

The perimeter is the sum of the lengths of the traingle. So,
P = 12x2 - 6
Plugging in the given value of x,
P = 12 (1.5)^2 - 6
P = 21 inches

Assuming that the ends of the straw are not overlapping in forming the triangle, the perimeter is just equal to the original length of the straw.

Jason estimates that his car loses 12% of its value every year. The initial value is $12,000. Which best describes the graph of the function that represents the value of the car after x years?

Answers

Answer:

$y=12,000*(0.88)^x$

Step-by-step explanation:

Please find the attachment.

We have been given that Jason estimates that his car loses 12% of its value every year. The initial value is $12,000.

Since the value of car is decreasing exponentially, so we will use exponential decay function to find the graph that represents the value of the car after x years.

An exponential decay function is in form: $y=a*(1-r)^x$ , where,

a = Initial value,

r = Decay rate in decimal form.

Let us convert our given rate in decimal form.

$12\%=(12)/(100)=0.12$

Upon substituting our given values in decay function we will get,

$y=12,000*(1-0.12)^x$

$y=12,000*(0.88)^x$

We can see from our graph that as x approaches infinity, y approaches to zero, therefore, our graph will have a horizontal asymptote at y=0.

Therefore, the function $y=12,000*(0.88)^x$ represents the value of the car after x years.

ANSWER:

y= 12000*(0.88)x

Step-by-step explanation:

We have been given that Jason estimates that his car loses 12% o

Since the value of car is decreasing exponentially, so we will use exponential decay function to find the graph that represents the value of the car after x years.

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