The answer choices are in the picture
Answer:
Option B
and
Step-by-step explanation:
we have
The formula to solve a quadratic equation of the form is equal to
in this problem we have
so
substitute in the formula
Remember that
To solve the equation x^2 - 8x + 97 = 0 using the quadratic formula, substitute the coefficients into the formula and simplify the expression. In this case, the equation has no real solutions.
To solve the equation x^2 - 8x + 97 = 0 using the quadratic formula, first identify the coefficients in the equation. The quadratic formula is given by x = (-b ± sqrt(b^2 - 4ac)) / (2a). In this case, a = 1, b = -8, and c = 97. Substitute these values into the quadratic formula and simplify the expression to find the value(s) of x.
Using the quadratic formula, we have x = (-(-8) ± sqrt((-8)^2 - 4(1)(97))) / (2(1)). Simplifying further, we get x = (8 ± sqrt(64 - 388)) / 2. Continuing the simplification, we have x = (8 ± sqrt(-324)) / 2. Since the square root of a negative number is not a real number, the equation has no real solutions.
Therefore, the answer is that there are no real solutions to the equation x^2 - 8x + 97 = 0.
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(x-h)^2 +(y-k)^2 = r^2 is the equation for a circle centered at (h,k) and radius r
(x-2)^2 +(y- (-8))^2 = 11^2
(x-2)^2 +(y+8)^2 = 11^2
Answer:(x-2)^2 +(y+8)^2 = 11^2
Answer:
(x-2)^2 + (y+8)^2 = 11^2
Step-by-step explanation:
The standard equation of a circle with center at (h,k) and radius r is
(x-h)^2 + (y-k)^2 = r^2.
Filling in the given info, we get:
(x-2)^2 + (y+8)^2 = 11^2