Answer:
0.25 m
Explanation:
The intensity of the magnetic field around a current-carrying wire is given by:
where
where
is the permeabilty of free space
I is the current
r is the distance from the wire
In this problem, we know:
is the magnetic field
is the current in the wire
Re-arranging the equation, we can find the distance of the field from the wire:
a. True
b. False
The magnitude of each charge is 3.94 x coulombs.
We have a pair of equal charges are separated by 0.75 m and there's a 2500 N force acting on them.
We have to strength of the charge.
According to Coulomb's law, the formula to calculate the force between the two point charges (say q and Q) separated by a some distance (say r) is given by -
F =
According to the question -
Force between two point charges equals to = F = 2500 N
Distance between the point charges = 0.75 m
Let's assume the magnitude of each charge be x, therefore using the coulomb's law, we get -
F =
coulombs
Hence, the magnitude of each charge is 3.94 x coulombs.
To understand more about coulomb's law visit the link below -
#SPJ2
Answer:
4.5643546 × 10^ -4
Explanation:
When Ernest Rutherford aimed a beam of particles at a thin gold foil he expected that the particles would be deflected slightly after passing through the foil.
Keywords: Atom, Rutherford experiment, gold foil, nucleus of an atom, setbacks of Rutherford's model
Level: High school
Subject: Chemistry
Topic: Structure of an atom and Atomic models
Sub-topic: Rutherford's and Bohr's model