The ziggurat linked the people of Mesopotamia to what? all of the gods they worshipped
ruler of their city
patron god of their city
all of the rulers in the civilization

Answers

Answer 1

Answer:

Answer: C

Step-by-step explanation: Patron God Of Their City

Related Questions

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The gazebo in the park is an octagon each side is 4 feet long what is the perimeter of the gazebo
.Resolva as equações, sendo U = Q (separe as respostas por vírgulas). A) 3y - 2 = - y + 4 B) 5 - 4x = x + 3 + 2x C) - 12 - 9x = - 4 - 12x D) - x - 6 + 3x = -2x + 8x + 15
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Which describes how the parent function, f(x) = |x|, is transformed to show the function f(x) = 0.1|x – 3|? A.It is wider and shifted 3 units to the left.
b. It is wider and shifted 3 units to the right.
c. It is narrower and shifted 3 units to the left.
d It is narrower and shifted 3 units to the right.

Answers

Transformation involves changing the position of a function.

The true statement is: (b) It is wider and shifted 3 units to the right.

The function is given as:

$\mathbf{f(x) = |x|}$

First, the function is translated right by 3 units.

So, we have:

$\mathbf{f'(x) = |x - 3|}$

Next, the function is enlarged horizontally by a factor of 0.1.

So, we have:

$\mathbf{f$

The above highlights mean that:

$\mathbf{f$ will be wider than $\mathbf{f(x) = |x|}$

Hence, the correct option is (b)

Read more about function transformations at:

brainly.com/question/13810353

Since u are solving
For f(x) u would be moving to the right being that it is a decimal times to a negative number so the answer would be B

Please what is the vertex and the point of this graph k (×)=[2 (×+4)]^2+3

Answers

The vertex form of a quadratic is given by
y = a(x – h)^2 + k, where (h, k) is the vertex ;
In your case , ( - 4 , 3 ) is the vertex ;

k(x) = 2(x + 4)² + 3
k(x) = 2(x + 4)(x + 4) + 3
k(x) = 2(x² + 4x + 4x + 16) + 3
k(x) = 2(x² + 8x + 16) + 3
k(x) = 2(x²) + 2(8x) + 2(16) + 3
k(x) = 2x² + 16x + 32 + 3
k(x) = 2x² + 16x + 35
2x² + 16x + 35 = 0
x = -(16) +/- √((16)² - 4(2)(35))
2(2)
x = -16 +/- √(256 - 280)
4
x = -16 +/- √(-24)
4
x = -16 +/- 2i√(6)
4
x = -4 + 0.5i√(6)
x = -4 + 0.5i√(6) x = -4 - 0.5i√(6)
k(x) = 2x² + 16x + 35
k(-4 + 0.5i√(6)) = 2(-4 + 0.5i√(6))² + 16(-4 + 0.5i√(6)) + 35
k(-4 + 0.5i√(6)) = 2(-4 + 0.5i√(6))(-4 + 0.5i√(6)) + 16(-4) + 16(0.5i√(6)) + 35
k(-4 + 0.5i√(6)) = 2(16 - 2i√(6) - 2√(6) + 0.25i²√(36)) - 64 + 8i√(6) + 35
k(-4 + 0.5i√(6)) = 2(16 - 4i√(6) + 0.25i²(6)) - 64 + 8i√(6) + 35
k(-4 + 0.5i√(6)) = 2(16 - 4i√(6) + 1.5i²) - 64 + 8i√(6) + 35
k(-4 + 0.5i√(6)) = 2(16 - 4i√(6) + 1.5(-√(1²)) - 64 + 8i√(6) + 35
k(-4 + 0.5i√(6)) = 2(16 - 4i√(6) + 1.5(-√(1 × 1)) - 64 + 8i√(6) + 35
k(-4 + 0.5i√(6)) = 2(16 - 4i√(6) + 1.5(-√1) - 64 + 8i√(6) + 35
k(-4 + 0.5i√(6)) = 2(16 - 4i√(6) + 1.5(-1)) - 64 + 8i√(6) + 35
k(-4 + 0.5i√(6)) = 2(16 - 4i√(6) - 1.5) - 64 + 8i√(6) + 35
k(-4 + 0.5i√(6)) = 2(16) - 2(4i√(6)) - 2(1.5) - 64 + 8i√(6) + 35
k(-4 + 0.5i√(6)) = 32 - 8i√(6) - 3 - 64 + 8i√(6) + 35
k(-4 + 0.5i√(6)) = 32 - 3 - 64 + 35 - 8i√(6) + 8i√(6)
k(-4 + 0.5i√(6)) = 29 - 64 + 35 + 0i√(6)
k(-4 + 0.5i√(6)) = -35 + 35 + 0
k(-4 + 0.5i√(6)) = 0 + 0
k(-4 + 0,5i√(6)) = 0
(x, k(x)) = (-4 + 0.5i√(6), 0)
or
k(x) = 2x² + 16x + 35
k(-4 - 0.5i√(6)) = 2(-4 - 0.5i√(6))² + 16(-4 - 0.5i√(6)) + 35
k(-4 - 0.5i√(6)) = 2(-4 - 0.5i√(6))(-4 - 0.5i√(6)) + 16(-4) - 16(0.5i√(6)) + 35
k(-4 - 0.5i√(6)) = 2(16 + 2i√(6) + 2i√(6) + 0.25i²√(36)) - 64 - 8i√(6) + 35
k(-4 - 0.5i√(6)) = 2(16 + 4i√(6) + 0.25i²(6)) - 64 - 8i√(6) + 35
k(-4 - 0.5i√(6)) = 2(16 + 4i√(6) + 1.5i²) - 64 - 8i√(6) + 35
k(-4 - 0.5i√(6)) = 2(16 + 4i√(6) + 1.5(-√(1²)) - 64 - 8i√(6) + 35
k(-4 - 0.5i√(6)) = 2(16 + 4i√(6) + 1.5(-√(1 × 1)) - 64 - 8i√(6) + 35
k(-4 - 0.5i√(6)) = 2(16 + 4i√(6) + 1.5(-√(1)) - 64 - 8i√(6) + 35
k(-4 - 0.5i√(6)) = 2(16 + 4i√(6) + 1.5(-1)) - 64 - 8i√(6) + 35
k(-4 - 0.5i√(6)) = 2(16 + 4i√(6) - 1.5) - 64 - 8i√(6) + 35
k(-4 - 0.45i√(6)) = 2(16) + 2(4i√(6)) - 2(1.5) - 64 - 8i√(6) + 35
k(-4 - 0.5i√(6)) = 32 + 8i√(6) - 3 - 64 - 8i√(6) + 35
k(-4 - 0.5i√(6)) = 32 - 3 - 64 + 35 + 8i√(6) - 8i√(6)
k(-4 - 0.5i√(6)) = 29 - 64 + 35 + 0i√(6)
k(-4 - 0.5i√(6)) = -35 + 35 + 0
f(-4 - 0.5i√(6)) = 0 + 0
f(-4 - 0.5i√(6)) = 0
(x, k(x)) = (-4 - 0.5i√(6), 0)

The point of the graph is (-4 + 0.5i√(6), 0), or (-4 + 0.5i√(6), 0) and (-4 - 0.5i√(6),0). The vertex of the graph is (-4, 3).

The original price of an electric scooter was $187.50. The scooter was on sale for $165. What was the discount rate?

Answers

so the origiinal price is 187.50 and the sale price was 165, so the discount is 187.50 - 165 = 22.5.

if we take 187.50 to be the 100%, what is 22.5 off of it in percentage?

$\bf \begin{array}{ccll} amount&\%\n \cline{1-2} 187.5&100\n 22.5&x \end{array}\implies \cfrac{187.5}{22.5}=\cfrac{100}{x}\implies 187.5x=2250 \n\n\n x=\cfrac{2250}{187.5}\implies x=12$

Answer: I got 12% after trial an error from 15% down to 12% when i got 165$

Use the method of quadrature to estimate the area under the curve y=-x^2+5 and above the x-axis from x=0 to x=2.

Answers

Answer:

Area = $(22)/(3)$

Step-by-step explanation:

Given is a curve

$y=-x^2+5$

we have to find the area of this curve above x axis from 0 to 2

By method of quadrature we know that area of a curve above x axis is given by,

$\int\limits^a_bf( {x} )\, dx$

Here a= 0 and b =2

Substitute to get

Area = $\int\limits^0_2 {-x^2+5} \, dx \n=(-x^3)/(3) +5x$

Substituting limits

Area = $(-8)/(3) +10 =(22)/(3)$

I'm a calculus teacher at the high school level and I have never heard of quadrature. I teach from an AP approved college-level text so...I'll do it using the antiderivative! Setting that up to integrate we have $- \int\limits^2_0 { (x^2-5)} \, dx$ . If you notice, I pulled the negative out in front of the integral and changed the signs in the function. So it could really be rewritten as $-1 \int\limits^2_0 {(x^2-5)} \, dx$ . Integrating we have $-1[ (x^3)/(3) -5x]$ from 0 to 2. Subbing in those bounds, we have $-1[( (2^3)/(3)-5(2))-( (0^3)/(3)-5(0))]$ which simplifies to $-1( (8)/(3)-10)$ . Distributing the -1 in gives us $10- (8)/(3)= (22)/(3)$

Find the volume of a right circular cone that has a height of 2.6 in and a base with a diameter of 5.7 in. Round your answer to the nearest tenth of a cubic inch.

Answers

The volume of a right circular cone is 22.11 in³.

What are algebraic expressions?

In mathematics, an expression or mathematical expression is a finite combination of symbols that is well-formed according to rules that depend on the context.

Mathematical symbols can designate numbers (constants), variables, operations, functions, brackets, punctuation, and grouping to help determine order of operations and other aspects of logical syntax.

Given is a right circular cone that has a height of 2.6 in and a base with a diameter of 5.7 in.

The volume of a right circular cone is -

V = {πr²h/3}

V = {π(d/2)²h/3}

V = {πd²h/12}

V = {3.14 x 5.7 x 5.7 x 2.6}/12

V = 22.11 in³

Therefore, the volume of a right circular cone is 22.11 in³.

To solve more questions on cones, visit the link below-

brainly.com/question/1984638

#SPJ6

Answer:

22.12 cubic inch rounded to the nearest tenth is 22.1 cubic inch.

Step-by-step explanation:

Nastasha has a gross income of $66,429. She can make adjustments of $14,490 for business losses, $3,584 for business expenses, and $4,813 for contributions to her retirement plan. What is Nastasha’s adjusted gross income?a.
$109,971
b.
$22,887
c.
$72,522
d.
$43,542

Answers

Initial gross income = 66429

business losses = 14490
business expenses = 3584
retirement plan = 4813

Adjusted gross income
66429 - (14490+3584+4813)
66429 - 22887
43542

Therefore the answer d is correct

the answer would be D because

66,429-14,490=51939

51,939-3,584=48,355

48,355-4,813=43,542

hope i helped

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