During year 1, Franklin's sign read "Franklin: Population of 20,000", while Chester's sign read
"Chester: Population of 25,000". Each year, the populations grew. Specifically, Franklin's population grew by
5% each year, and Chester's population grew by 500 people each year.
What is the first year in which Franklin's sign shows a larger number than Chester's sign?
Answer:
Franklin's population < Chester's population by 4500
Step-by-step explanation:
Franklin: 20000 (1 + 0.05) = 21000 (21000 - 20000 = 1000 grew)
Chester: 25000 + 500 = 25500 (500 increase)
To find the first year in which Franklin's sign shows a larger number than Chester's sign, we set up an equation and solve for the year. The first year is year 6.
To find the first year in which Franklin's sign shows a larger number than Chester's sign, we need to set up an equation and solve for the year. Let's denote the year as 'y'.
Franklin's population can be represented as: 20000 + (20000 * 0.05 * y).
Chester's population can be represented as: 25000 + (500 * y).
Setting up the equation, we have: 20000 + (20000 * 0.05 * y) > 25000 + (500 * y).
Simplifying the equation, we get: 1000 * y > 5000.
Dividing both sides of the equation by 1000, we find that y > 5.
Therefore, the first year in which Franklin's sign shows a larger number than Chester's sign is year 6.
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show your work
Answer:
$18,000
Step-by-step explanation:
Target is 3000, out of which 1200 will already be earned from salary. So he needs 3000 - 1200 = 1800 from commissions.
As we know, 10% is the commission rate, we need to know "Which numbers' 10% will give us 1800??"
Thus let total sales be x, so we can write 0.1x=18,000
Solving gives us:
He needs to sell $18,000 worth of merchandise to meet his income target for July.