Lu is making a quilt that is 20 squares wide and has 24 rows. The border of the quilt is made by using each design equally as often. Each square can hold one design. How many of each design does she use for the border?

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Answer 1

Answer: Here is the correct answer for this question

The quilt has 4 sides.
The border will have 20 squares two times, and 24 squares two times as well, that is the perimeter or the border.
= 20*2 + 24*2
= 40 + 48
= 88

So, from the answer above, the border will have 88 squares total.
Lu can use any toy design 88 times.

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I need help!! I need to pass math!! Please help I know it's a lot but I need help I don't get any of this!

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I hope this helps a little!!! but if you need more details just ask

A triangle has two sides of length 5 and 12. what value could the length of the third side be? More then one can be correct.a.7
b.5
c.19
d.17
e.11
f.9

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$Condition\ for\ existing\ triangle\n\n a,b,c- sides\ of\ triangle\n\n a+b>c\na+c>b\nb+c>a\n 5+12=17\n\n a)\ 7<5+12,\ 5+7>12 \ , 7+12>5 \n b)\ 5<5+12,\ \ 5+5\not>12\nc)19\not<5+12\nd)17\not<5+12\ne)11<12+5,\ \ 11+5>12,\ 11+12>5 \nf)9<12+5,\ \9+5>12\ \ 12+9>5 \n\Third \side\ can\ be\ a,e,f$

An isosceles triangle has two sides of equal length. The third side is 5 less than twice the length of one of the other sides. If the perimeter of the triangle is 23 cm, what is the length of the third side?Explain how you would define a variable for this problem.

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let's take one side of the two equal lengths as r
third side is s.
so the total perimeter is r + r + s
2r + s = 23

According to the statement of third side s,
5 less than twice the length of one of other
s = 2r - 5

we have 2 equations and 2 unknowns. so we can find out the values of those letters.

2r + s = 23
2r - s = 5

4r = 28
r = 7

s = 9
Therefore the third length will be equal to 9 cm.

Answer:

x+x+(2x-5)=23

Step-by-step explanation:

What is the coefficient monomial of 5pk

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The coefficient is the numbers that come before the variables, so in this case your answer is 5

Find the GCF of the following literal terms. m^7 n^4 p^3 and mn^12 p^5

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Do you have the 4th problem typed correctly? The two given numbers have no factor (other than 1) in common (i.e., they are relatively prime) so the GCF is 1.

48 = 2^4 * 3

Therefore, GCF of 16a^4 b^4 + 32a^3 b^5 - 48a^2 b^6 is 16a^2 b^4, so
16a^4 b^4 + 32a^3 b^5 - 48a^2 b^6 = (16a^2 b^4)(a^2 + 2ab - 3b^2) = (16a

Please correct me if I’m wrong

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Answer:

1 = No, 2 is correct, 3 = No, 4 is correct.

Step-by-step explanation:

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