An object has a density of 20 g/cm 3 . When placed in a cylinder, it displaces 5 mL of water. What is the mass of the object?

Answers

Answer 1

Answer: Note 1mL = 1cm³

5mL = 5cm³.

If it displaces 5mL of water which is equivalent to 5cm³, then its volume is also 5cm³

Density = Mass / Volume

20 g/cm³ = Mass / 5 cm³

Mass = 20 g/cm³ * 5 cm³

Mass = 100 g.

Answer 2

Answer:

Answer:

100grams

Explanation:

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The total rate of energy use in the United States is now such that each person has the equivalent of about ___ horsepower working continuously.98.3 QBtu/year29 million people in the U.S.Horsepower= 746 WThe above is the info you will need. This is what I have done so far, but it can NOT be right:98.3*10^15Btu/year(1 year/365 days) = 0.269315*10^15 Btu/day (0.269315*10^15Btu/day)/291 million = (0.2693*10^15 Btu/day)/291*10^6 ~0.00092548109*10^5 Btu/day = 925,481.09Btu/day 925,481.09Btu/day*(1day/24hour) = 38561.71 Btu/hour ~ 38561.7Btu/hour1horsepower = 746 W 1 W = 3.412Btu/hr38561.7Btu/hr*(1 W/3.412 Btu/hr) ~ 11301.3 W*(1 hp/746 W) = 15.149 hp

A 70kg divers steps off of a 10m tower and drops from rest straight into the water. If he comes to rest 5m beneath the surface, determine the average resistance force exerted on him by the water.

Answers

Kinetic Energy:
K E= m g h
h = 10 m, d = 5 m.
m g ( h + d ) - F d = 0
m g ( h + d ) = F d
70 * 9.8 * 15 = F * 5
10,290 = 5 F
F = 10,290 : 5
F = 2,058 N

First, we need to calculate the total distance that the diver travelled. The diver jumped off a 10-meter tower and went 5 meters under the water. Therefore, the total distance travelled by the diver is 10 meters (from the tower) plus 5 meters (underwater), which equals 15 meters.

Next, we will determine the work done on the diver. The work done is equal to the change in potential energy, which can be calculated by multiplying the diver's mass by gravity and then by the total distance the diver travelled. Given that the diver's mass is 70kg and the acceleration due to gravity is 9.8m/s², the work done is 70kg * 9.8m/s² * 15m, which equals 10290 Joules.

Finally, we'll find the average resistance force exerted on the diver by the water. The work done on the diver is also equal to the average force times the distance. Therefore, the average force is the work done divided by the distance. When you divide the work done (10290 Joules) by the total distance travelled (15 meters), you get an average force of 686 Newtons.

Hence, the total distance travelled by the diver in water is 5 meters, the work done on the diver is 10290 Joules, and the average resistance force exerted on the diver by the water is 2058 Newtons.

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Distance measurements based on the speed of light; used for objects in space

Answers

Answer : Yes, distance measurements based on the speed of light used for objects in space.

Explanation : A light year is measurement of distance that light travel in a one year.

In a one year light travels 9460000000000 kilometer.

We know that, speed of light is $3*10^(8)\ m/s$

and time is 31536000 seconds in 1 year

so, distance= speed of light X time

Now, the light year is $9.4608*10^(15) meter$

Example : The nearest star to earth is about 4.3 light year away.

An object of the same mass has three different weights at different times. Which statement is possible?

Answers

So we want to know how can an object have three different weights at different times. So weight is Fg=m*g, where m is the mass of the objecct and g is the gravitational acceleration. On Earth, g=9.81 m/s^2, in space g is much less and on the moon g=1.625 m/s^2 So we see that the object changes its weight by moving it to space and on the Moon.

The object started on earth, was transported to space,and was deposited on the moon

It would be appreciated if all questions were answered and have shown work. :)1. While skiing, Sam flies down a hill and hits a jump. He has a mass of 75 kg, and he leaves the jump at 18 m/s. What is his momentum as he leaves the jump?

2. How fast would a 0.25 kg football have to be traveling to have the same momentum as a 0.05 kg bullet travelling 500 m/s?

3. Sarah, who has a mass of 55 kg, is riding in a car at 20 m/s. She sees a cat crossing the street and slams on the brakes! Her seat-belt stops her from flying forward, bringing her to rest in 0.5 seconds. How much force did the seat-belt put on Sarah?

Answers

1. The formula for momentum is:
p = mv
p =75(18) = 1350 kg-m/s

2. We equate the momentum of the two objects
0.25 v = 0.05 (500)
v = 100 m/s

3. We use the formula for impulse:
Δmv = FΔt
55(20) = F(0.5)
F = 2200 N

P = mv

P=75 (18) = 1350 kg-m/s

0.25 v= 0.05 (500)

V= 100 m/s

∆ mv = F∆t

55(20) =F(0.5)

The yoga term asanas are which of the following?A.
The yoga breathing method.
B.
The yoga term for mediation.
C.
The yoga term for exercises or poses.
D.
The yoga term for spiritual enlightenment.

Answers

Answer:

i guss its A

Explanation:

Suppose you hit a 0.058-kg tennis ball so that the ball then moves with an acceleration of 10 m/s2. if you were to hit a basketball of mass 0.58 kg with the same force, what would the acceleration a of the basketball be? *graph is 4/x if that helps.

Answers

In this problem, the working equation to be used is the Newton's 2nd law of motion: Force = mass x acceleration.

First situation: mass = 0.058 kg; acceleration = 10 m/s2

Hence, force is 0.058 kg x 10 m/s2, which is 0.58 N. Since same force is to be used, this same value is used for the second situation.

Second situation: mass = 0.58 kg; Force = 0.58 N

Since F = ma, by transposing, the acceleration could be solved by the equation, a = F/m. Thus, 0.58N/0.58 kg, the acceleration is 1 m/s2.

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