the ratio of cats to dogs seen by a veterinarian in one day is 2 to 5. If a vet saw 40 dogs in one day,how many cats did he see?

Answers

Answer 1

Answer:

If the number of dogs seen by the veterinarian is 40 then the number of cats seen by him will be equal to 16.

What is the ratio?

The ratio notion is used in mathematics when evaluating two or more numbers. It works as a comparison tool to demonstrate how big or small a particular number is. A ratio divides two quantities in order to compare them.

As per the data given in the question,

The ratio of cats to dogs seen by veterinarian = 2:5

Number of dogs seen by veterinarian = 40

Let the number of cats seen by him be x.

Then, the ratios will be,

C : D

2 : 5

x : 40

Use cross-multiplication to find the number of cats,

5x = 2 × 40

x = (2 × 40)/5

x = 2 × 8

x = 16

To know more about Ratios:

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Answer 2

Answer: 2 cats to every 5 dogs
x cats to every 40 dogs

x/40 = 2/5
(here you can cross multiply OR multiply the second fraction by 8/8)

x = 16 the vet saw 16 cats

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So there were Total of 3 football games a month and 9 were played at night the season is played for 4 months how many games are in the season

Answers

If the season lasts 4 months and there were a total of 3 games played per month, there are 12 games in a season.

4 x 3 = 12

The information about how many games were played at night is useless and just trying to confuse you. :)

Help i dont know how to solve it and i dont have my teachers number im homeschooled

Answers

I believe it would be 9a + 3b + c = 3 but it's been awhile since I've done this...

What are the solutions to x3=5−5i in polar forma. 52‾√3cis(23π12)

b. 52‾√3cis(5π4)

c. 50‾‾‾√6cis(23π12)

d. 50‾‾‾√6cis(7π12)

e. 50‾‾‾√6cis(4π3)

f. 50‾‾‾√6cis(5π12)

g. 50‾‾‾√6cis(5π4)

h. 52‾√3cis(7π12)

i. 52‾√3cis(5π12)

Answers

Answer:

$z_1=(5√(2))^(1/3)cis((7\pi)/(12))$

Step-by-step explanation:

To find the roots of the complex number you use the following formula:

$z=re^(i\theta)\n\nz_k= (r)^(1/n)[cos((\theta+2\pi k)/(n))+sin((\theta+2\pi k)/(n))];\ \ k=0,1,2..n-1$ (1)

in this case the polar number in polar form is:

$r=√(5^2+5^2)=5√(2)\n\n\theta=tan^(-1)((-5)/(5))=-45\°$

By replacing in (1) you obtain:

$z_0=(5√(2))^(1/3)cis((-\pi/4+0)/(3))\n\nz_1=(5√(2))^(1/3)cis((-\pi/4+2\pi)/(3))=(5√(2))^(1/3)cis((7\pi)/(12))\n\nz_2=(5√(2))^(1/3)cis((-\pi/4+4\pi)/(3))=(5√(2))^(1/3)cis((15\pi)/(12))$

hence, you have:

h. 52‾√3cis(7π12)

X and Y are continuous values, both measured to 2 significant figures. X=230 and Y=400. work out the greatest possible value of X/Y^2.(this is on an upper and lower bounds sheet)

Answers

"Two significant figures" means that a digit after the second one could actually be anything ... it wasn't measured. 'X' could be anything from 230 to 239. 'Y' could be anything from 400 to 409.The greatest possible value of that fraction is. (239)/(409 squared) .

together Xavier,Yolanda,and Zachary have $4.44 . if each person has the same amount , how much money does each person have?

Answers

If their are 3 of them and they all have the same amount, and the finishing total is $4.44, Then they would each have $1.48. If you need the work take $4.44 and divide it by 3.

$1.48 because $4.44 divided by 3 equals $1.48

What is 4z - 3/z + 6 when z = −3?

I need this asap!!

Answers

4(-3)-3/(-3)+6
PEMDAS
4(-3)=-12
-3/-3=1
-12+1=-11
-11+6
-5

-5 is what I got, if you plug in -3 where z is.

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