its B on edge-nuity just took the test
The lines 2x + ky = 3 and kx + 8y = 7 intersect for all values of k except 4 and -4 the answer is R - {4, -4}.
It is defined as the relation between two variables, if we plot the graph of the linear equation we will get a straight line.
If in the linear equation, one variable is present, then the equation is known as the linear equation in one variable.
It is given that:
Two linear equations in two variables are:
2x + ky = 3 and
kx + 8y = 7
As we know the condition for the lines to intersect or have unique solutions:
2/k ≠ k/8
After cross multiplication:
k² ≠ 16
k ≠ ±4
The values of k can be anything except 4 and - 4
Thus, the lines 2x + ky = 3 and kx + 8y = 7 intersect for all values of k except 4 and -4 the answer is R - {4, -4}.
Learn more about the linear equation here:
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Answer:
ky=3-2x
y=(3-2x)/k
y=(7-kx)/8
(3-2x)/k=(7-kx)/8
8(3-2x)=(7-kx)k
24-16x=7k-k*kx
24=7k-kkx+16x
24+7k=kkx+16x
24+7k=x(k^2+16)
B. 2b − 6
C. 2(b − 6)
D. b ÷ 6