Answer:
A.) 20
Step-by-step explanation:
(40/25)*12.5=20
Hope this helps.
Answer:
x = 90 - 2α
Step-by-step explanation:
Solution:-
- Consider the right angled triangle " ABD ". The sum of angles of an triangle is always "180°".
< BAD > + < ADB > + < ABD > = 180°
< ABD > = 180 - 90° - α
< ABD > = 90° - α
- Then we look at the figure for the triangle "ABE". Where " E " is the midpoint and intersection point of two diagonals " AC and BD ".
- We name the foot of the perpendicular bisector as " F ": " BF " would be the perpendicular bisector. The angle < BAE > is equal to < ABD >.
< ABD > = < BAE > = 90° - α ... ( Isosceles triangle " BEA " )
Where, sides ( BE = AE ).
- Use the law of sum of angles in a triangle and consider the triangle " BFA " as follows:
< ABF> + < BFA > + < BAF > = 180°
< ABF > = 180 - (90° - α) - 90°
< ABF > = α
Where, < BAF > = < BAE >
- The angle < ABD > = < ABE > is comprised of two angles namely, < ABF > and < FBE > = x.
< ABD > = < ABE > = < ABF > + x
90° - α = α + x
x = 90 - 2α ... Answer
Answer:
Step-by-step explanation:
The length of this triangle is 10 squares
and the width is 4 squares
The diagonals divide the rectangle into four triangles
These traingles are isoceles
Each two triangles facing each others are identical
<B = 90 degree
B = alpha + Beta
Let Beta be the angle next alpha
The segment that is crossing Beta is its bisector since it perpendicular to the diagonals wich means that:
Beta = 2x
Then B = alpha + 2x
90 = alpha +2x
90-alpha = 2x
x = (90-alpha)/2
Answer:
The answer is given below
Step-by-step explanation:
a) What is the probability that a randomly selected pregnancy lasts less than 242 days
First we have to calculate the z score. The z score is used to determine the measure of standard deviation by which the raw score is above or below the mean. It is given by:
Given that Mean (μ) = 247 and standard deviation (σ) = 16 days. For x < 242 days,
From the normal distribution table, P(x < 242) = P(z < -0.3125) = 0.3783
(b) Suppose a random sample of 17 pregnancies is obtained. Describe the sampling distribution of the sample mean length of pregnancies.
If a sample of 17 pregnancies is obtained, the new mean the new standard deviation:
c) What is the probability that a random sample of 17 pregnancies has a mean gestation period of 242 days or less
From the normal distribution table, P(x < 242) = P(z < -1.29) = 0.0985
d) What is the probability that a random sample of 49 pregnancies has a mean gestation period of 242 days or less?
From the normal distribution table, P(x < 242) = P(z < -2.19) = 0.0143
(e) What might you conclude if a random sample of 49 pregnancies resulted in a mean gestation period of 242 days or less?
It would be unusual if it came from mean of 247 days
f) What is the probability a random sample of size 2020 will have a mean gestation period within 11 days of the mean
For x = 236 days
For x = 258 days
From the normal distribution table, P(236 < x < 258) = P(-3.07 < z < 3.07) = P(z < 3.07) - P(z < -3.07) =0.9985 - 0.0011 = 0.9939
simplify 3^5 x 3^4