A telephone pole is 60 feet tall. It casts a shadow that's is 24 feet long. A tree that's is next to the flag pole casts a shawdow that's is 4ft tall. How tall is the tree

Answers

Answer 1
Answer: ok so ratios
height:shadow =60:24
fractionify
60/24=5/2

5:2 is ratio
if shadow of tree=4 then what is height
5:2=x:4
multipliby 2
10:4=x:4
x=10
10 feet

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Can someone help me on # 4
And tell me if I set it up right??

Answers

yup you did it better than I would have

A force of 200 N is exerted onan object of mass 40 kg that is
located on a sheet of perfectly
smooth ice. Calculate the
acceleration of the object.

Answers

The acceleration of the object is 5 m/s^2

Step-by-step explanation:

Given

Mass of object = m = 40 kg

Force = F = 200 N

Newton's 2nd law states that:

F = ma

As we have to find the acceleration

a = (F)/(m)

Putting the values

a = (200)/(40)\na = 5\ ms^(-2)

The acceleration of the object is 5 m/s^2

Keywords: Force, acceleration

Learn more about force at:

#LearnwithBrainly

Final answer:

To calculate the acceleration of the object, we can use Newton's second law of motion which states that the acceleration of an object is directly proportional to the net force applied to it and inversely proportional to its mass. Using the given force of 200 N and mass of 40 kg, we can determine that the acceleration of the object is 5 m/s^2.

Explanation:

To calculate the acceleration of the object, we can use Newton's second law of motion which states that the acceleration of an object is directly proportional to the net force applied to it and inversely proportional to its mass.

  1. First, we need to determine the net force acting on the object. In this case, it is given as 200 N.
  2. Next, we need to determine the mass of the object, which is given as 40 kg.
  3. Using the formula: acceleration = net force / mass, we can substitute the given values to find the acceleration.
  4. Substituting the values, we get: acceleration = 200 N / 40 kg = 5 m/s^2.

Therefore, the acceleration of the object is 5 m/s^2.

Learn more about Calculating acceleration here:

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How much does this equal?

Answers

1 Set up the long addition.

12+42

2 Calculate 2 + 2, which is 4.

12+424
3 Calculate 1 + 4, which is 5.

12+4254
4 Therefore, 12 + 42 = 54.
54

Hey there

Solutions 

12 + 42 
= 54 

CHECK YOUR WORK 
54 - 12 
= 42 

The answer was correct 

What is a system of equations?

Answers

Answer and Step-by-step explanation:

A system of equations is a group of equations that need to be manipulated in some way that will figure out the values of the variables.

The most common system of equations seen is a system of linear equations, which means that the degree of the variables is no more than 1. These can be solved using elimination, substitution, or even graphing, if applicable.

Hope this helps!

Answer:

A system of equations is 2 or more equations that need to be solved. When you solve a system of equations, the answer is where the equations intersect on a graph. Sometimes there is 2 solutions (equations intersect twice), 1 solution (equations intersect once), no solution (equations don't intersect), or infinite solutions ( equations are the same).

They are usually solved using substitution, elimination, or simply looking at a graph to see where the lines intersect.

Some examples:

2x+3y=15

x-3y=3

y=x^2+1

2x-y= -4

a fugitive has escaped in a train wreck. the police believe he could not have traveled more than 7 mi in any direction from the wreck. how many square miles must be searched?

Answers

the police believe he could not have traveled more than 7 mi in any direction from the wreck. 

This 7 mi represents the radius of the circular area they need to search. Sp the fomula for the area of a circle :

A = pi(r^2)

Where r is the radius

 

A = pi( 7^2)

A = 153.94 sq mi thy need to search

Is x-3/5 = N and N = 6, what is the value of x?

Answers

Answer:

x = 33/5

Step-by-step explanation:

x - 3/5 = n.......n = 6

so we sub

x - 3/5 = 6......add 3/5 to both sides

x = 6 + 3/5...convert using common denominator of 5

x = 30/5 + 3/5

x = 33/5 <===

check...

x - 3/5 = 6

33/5 - 3/5 = 6

30/5 = 6

6 = 6 (correct)...so it checks out

X=33/5 is the value