a train traveled at an average speed of 45 miles per hour for 2 hours and 30 miles per hour for 3 hours. what is the total number of miles that the train traveled
Answers
rate=xmiles per hour
time=y hours
total distance=distance1+distance2
distance1=45mph times 2=90mi
distance2=30mph times 3=90mi
total distance=90mi+90mi=180mi
total is 180mi
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Answers
-5 - 4= -9
so it's
x-3=-9 OR
x=-6
x-3=-9
x=-6
Answers
Answer:
B
Step-by-step explanation:
The others are of the form y=mx+c which is the definition of a linear function
Answers
Answers
Answer:
what is the question exactly??
can you please elaborate...
Step-by-step explanation:
Answers
The required height of the tree is 32.5 meters.
Given that,
A person 100 meters from the base of a tree, observes that the angle between the ground and the top of the tree is 18 degrees. To estimate the height h of the tree to the nearest tenth of a meter.
What are trigonometric equations?
These are the equation that contains trigonometric operators such as sin, cos.. etc.. In algebraic operations.
Here,
let the height of the tree be x, and the slant height from the foot of the person to the top of the tree be h,
according to the question,
base length = 100
cos 18 = 100 / h
h = 105.14
Now,
sin 18 = x / h
sin 18 = x / 105.14
x = 32.5 meters
Thus, the required height of the tree is 32.5 meters.
Learn more about trigonometry equations here:
#SPJ2
This is right angle trig. We know that...
cos(18°) x hypotenuse = 100
hypotenuse = 100/cos(18°)
hypotenuse = 105.15 meters approx.
Because they want the height of the tree we want "sin(18°) x hypotenuse".
sin(18°) x 105.15 = 32.5 meters approx.
answer: 32.5 meters approx.
Answers
Answer:
Step-by-step explanation:
2) ∠A + ∠B = 146 {Exterior angle theorem}
5y + 3 + 4y + 8 = 146
5y + 4y + 3 + 8 = 146 {combine like terms}
9y + 11 = 146
9y = 146 -11
9y = 135
y = 135/9
y = 15
3) m∠A = 5y + 3
= 5*15 + 3
= 75 + 3
∠A = 78
4) m∠B = 4y + 8
= 4*15 + 8
= 60 + 8
m∠B = 68
5) m∠ACB + m∠A + m∠B = 180 {Angle sum property of triangle}
m∠ACB + 78 + 68 = 180
m∠ACB + 146 = 180
m∠ACB = 180 - 146
m∠ACB = 34