13/20+5/8
Can someone help me with this in steps?

Answers

Answer 1

Answer: First thing you need to do, in order to add straight across like this:
$(13)/(20) + (5)/(8)$
You need to set the denominators equal to each other, by finding out the greatest common multiple. Which in this case is 40.

$(2 * 13)/(2 * 20) + (5 * 5)/(5 * 8)$
When you multiply, whatever you do to the denominators you must do the same to the numerator. Our new fractions should now have equal denominators like below:
$(26)/(40) + (25)/(40)$
Now keeping the same denominators you can simply add together 26 and 25
$26 + 25 = 41$
$(41)/(40)$
Now you need to simply this improper fraction, to get the final answer.

ANSWER:
$1 (1)/(40)$

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Rewrite using the distributive property and GCF 16 + 40

Answers

The GCF of 16 and 40 is 8.

16/8 = 2

40/8 = 5

We can rewrite this using the distribute property like so:

8(2 + 5)

Using the distributive property:

16 + 40

16 + 40 = 56

We can also add inside the parentheses and multiply and we'll get the same answer.

8(7)

B squared minus 7b plus 6

Answers

Answer:

(b-1)(b-6)

Step-by-step explanation:

recheck : -6×-1=6

-6-1= -7

b×b=b²

In a video game,a guppy that escapes a net turns into three goldfish.Each goldfish can turn into two betta fish.Each betta fish can turn into two angelfish.Write and evaluate an expression for the number if angelfish that can be formed from one guppy.

Answers

If g=guppy, go=goldfish, b=bettafish and a=angelfish we can set up expressions for each set of fish.
1g=3go
1go=2b
1b=2a

By working backwards and substituting we can finally work out 1 guppy to be equal to 12 angelfish.

How do you find the y intercept

Answers

Depends on if you are going off of a graph or an equation. In a graph, it is where a line crosses the y-axis. In an equation, it is the constant.

It is the vertical line on a graph. X is horizontal

The equation represents the function f, and the graph represents the function g. f(x)=6x-5A.

The rate of change of f is twice the rate of change of g.

B.

The rate of change of g is twice the rate of change of f.

C.

The rate of change of f is 3 times the rate of change of g.

D.

The rate of change of f is the same as the rate of change of g.