Using FOIL, solve (t + 2bs^2) (2t-3bs^2) please show all the steps.

Answers

Answer 1
Answer: foil
first
outer
inner
last
example if you had
(x+y)(z+t)
first x times z
outer x time t
inner y times z
last y times t


so

FOIL
(t+2bs^2)(2t-3bs^2)
FIRST (t times 2t=2t^2)
Outer (t times -3bs^2=-3tbs^2)
Inner (2bs^2 times 2t=4tbs^2)
Last (2bs^2 times -3bs^2=-6b^2s^4)

now add
2t^2-3tbs^2+4tbs^2-6b^2s^4
add like terms (-3tbs^2+4tbs^2=1tbs^2=tbs^2)
2t^2+tbs^2-6b^2s^4
Answer 2
Answer: 2t^2+-6b^2s^4+4bs^2t-3bs^2t

 so 2t^2-6b^2s^4+bs^2t is your answer 

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Simplify 5t + (t - 3) - [(7t + 5) - (8 - 3t)].

-4t
4t
-10t
10t

Answers

The simplification of the expression 5t + (t - 3) - [(7t + 5) - (8 - 3t)]  using PEMDAS rule is -4t.

Thus, option 1 is correct.

A method of reducing an expression, equation, or problem to a more concise or straightforward form is referred to as simplification.

Initially the small bracket then curly brackets and at last large brackets are required to solve according to the laws of simplification using PEMDAS rules.

The given expression can be simplified as:

5t + (t - 3) - [(7t + 5) - (8 - 3t)]

5t+t-3-[7t+5-8+3t]

5t+t -3-7t-5+8-3t

-4t

The simplification of the expression 5t + (t - 3) - [(7t + 5) - (8 - 3t)] is -4t.

Thus, option 1 is correct.

Learn more about expression here:

brainly.com/question/34132400

#SPJ6

 5t + (t - 3) - [(7t + 5) - (8 - 3t)] 
=5t + (t - 3) - [(7t + 5) - (-3t + 8)] 
=5t + (t - 3) - [7t + 5 + 3t - 8] 
=5t + (t - 3) - [7t + 3t + 5 - 8] 
=5t + (t - 3) - [10t - 3] 
=5t + t - 3 - 10t + 3 
=5t + t - 10t - 3 + 3 
=-4t

Is this correct ? .......................

Answers

To find the midpoint of the two points (x₁ ,y₁) and (x₂, y₂) we need to use the formula:

\sf{Midpoint=((x_1 + x_2)/(2), (y_1+y_2)/(2))}

So to find the midpoint of E (a,a) and F (3a, a), let's plug it in to the formula:

\sf{Midpoint=((a + 3a)/(2), (a+a)/(2))}

Simplify the numerator:

\sf{Midpoint=((4a)/(2), (2a)/(2))}

Simplifying the fractions more:

\sf{Midpoint=(2a, a)}


So the midpoint of EF is (2a,a).

Your answer of (a,a) would be wrong.

the lenghtvof each side of a square is 2.5 meter. if each side is doubled in length, what is the effect on the perimeter of the square? a.it remain the same b.it is one half the original perimeter c. it is four time the original perimeter d. it is twice the original perimeter.

Answers

Answer:

Step-by-step explanation:

Alright, lets get started.

The side length of square is given as 2.5.

So, the perimeter if square will be : 4*2.5=10.0

Once the side is doubled, means new dimension of side of square will be : 2*2.5=5

So the new perimeter will be : 4*5=20

The original perimeter is 10.

The new perimeter is 20.

It means the perimeter is twice the original perimeter.   :   Answer D

Hope it will help :)

T=4.5


Simplifying3t + 4 = t + 13
Reorder the terms:4 + 3t = t + 13
Reorder the terms:4 + 3t = 13 + t
Solving4 + 3t = 13 + t
Solving for variable 't'.
Move all terms containing t to the left, all other terms to the right.
Add '-1t' to each side of the equation.4 + 3t + -1t = 13 + t + -1t
Combine like terms: 3t + -1t = 2t4 + 2t = 13 + t + -1t
Combine like terms: t + -1t = 04 + 2t = 13 + 04 + 2t = 13
Add '-4' to each side of the equation.4 + -4 + 2t = 13 + -4
Combine like terms: 4 + -4 = 00 + 2t = 13 + -42t = 13 + -4
Combine like terms: 13 + -4 = 92t = 9
Divide each side by '2'.t = 4.5
Simplifyingt = 4.5



I got help from a website called geteasysolution

For a two week period, John and Amanda had the following transactions occur to their checking account: a deposit of $1,644.50; checks written for $190, $45, and $7.50; and debit card transactions for $30, $5.59, $7.20, and $21.30. What is the ending balance for this time frame?A. $1,377.91
B. $1,234.56
C. $1,352.24
D. $1,466.09

Answers

So we want to know what is the ending ballance if the starting value on the account was the deposit of 1644.5$ and debit card transactions were: 30$ + 5.59$ + 7.2$ + 21.3$= 64.09$ and checks: 190$ + 45$ + 7.5$= 242.5$. When we take those values from the initial value: 1644.5$-242.5$-64.09$= 1377.91$. And the correct answer is A.

How do you find a side length of a cube with the surface area of one face (64cm)

Answers

Fact #1:
A cube has six faces.

Fact #2:
Every one of them has the same area.

Fact #3:
The surface area of each face is (the length of the cube's side)²

Now that I look at this one more carefully, the only thing you need to know
to solve it is Fact #3.  (But you can keep the others and save them for later.)

The surface area of each face is (the length of the cube's side)²

64 is the (length of the cube's side)²

Can you find a number that gives you 64 when you multiply it by itself ?
That's the length of the cube's side.

Hint: If you don't get ' 8 ', work on it a little more.

if i get the fraction "2/2" and i need to reduce it would it be "1" or "2" like would it be 2 wholes or only 1??

Answers

parts/whole

if you have 2 parts and 2 are needed to make 1 whole, then you have 1 whole since
x/x=1 where x=x

it would be only 1
A fraction is a division problem, so 2/2 is also two divided by two.

Two goes into two only one time, so your answer is 1.