Cammile wants to make fruit drinks.The direction to make one drink include mixing 4 cup of yogurt and 1 cup of ice with the amount of each fruit shown8
5 cup of banana slice
8
2 cup of blueberries
8
Part A
Camille wants to make six drinks for her friends.How many total cups of blueberries and banana slices will she use to make the 6 drinks?Show your work
A:7
b. 12
c. 30
d. 42
8. 8. 8. 8
Part B
Next Camille will add the yogurt and ice.how many yogurt and ice will she use to make 6 drinks?Show your work or explain your answer.
Enter your answer and work or explanation in the space provided.

Answers

Answer 1

Answer: Given:
1 drink:
4/8 cup of yogurt ;
1 cup of ice;
5/8 cups of banana slices ;
2/8 cups of blueberries

Part A. 6 drinks. How many total cups of blueberries and banana slices will she use to make 6 drinks?

5/8 cups banana slices * 6 drinks = 5/8 * 6 = (5*6)/8 = 30/8 cups of banana slices.

2/8 cups of blueberries * 6 drinks = 2/8 * 6 = (2*6)/8 = 12/8 cups of blueberries

30/8 + 12/8 = 42/8 cups of banana slices and blueberries

Part B
4/8 cups of yogurt * 6 drinks = (4*6)/8 = 24/8 = 3 cups of yogurt
1 cup of ice * 6 drinks = 6 cups of ice

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Marissa rode her bike to the park and back home. She lives 2 3/10 miles from the park. How many miles did Marissa ride her bike in all. Give u 20 points

Answers

$2(3)/(10) +2(3)/(10) =((2*10)+3)/(10)+((2*10)+3)/(10) =(20+3)/(10)+(20+3)/(10)\n\n=(23)/(10) +(23)/(10) =(23+23)/(10) =(46)/(10) =4(6)/(10) =\boxed{\bf{4(3)/(5)}}$

Marissa rode 4 3/5 miles in all.

Well since she rode 2 3/10 to the park and back the problem would be 2 3/10 +2 3/10 which would equal 4 6/10
hope that helps.

Two cards are drawn in succession from a pack of 52 well-shuffled cards. find the probability that :1) only the first card is a king
2) first card is a jack of diamonds or a queen 3) at least one card is a picture card
4)not more than one card is a picture card
5) the cards and not of the same suit
6) the second card is not a heart
7) the second card is not a heart given that the first card is a heart
8) the cards are Aces or diamond or boats

Answers

Probabilities:
1) 4/52 * 48/51 = 192/2652 = 16/221
( explanation : 4- the number of kings, 52- the number of all cards on the pack, 48 - the number of other cards, 51- the number of cards that remain after picking first card)
2) (1/52+4/52) * 51/51 = 5/52 * 1 = 5/52
( in brackets are probabilities that 1st card is jack diamond or a queen )
3) 12/52 * 11/51 + 12/52 * 40/51 + 40/52 * 12/51= 91/221
( first is the probability that there are no picture cards, then one picture card: probability 12/52 * 40/51 that 1st is picture card and 40/51 * 12/52 that 2nd is a picture card)
4) 40/52 *39/51 + 12/52 *40/51 + 40/52 * 12/51= 210/221
5) 13/52 * 39/51= 169/884
( first is one suit and 2nd is another)
6) 39/52 * 38/51 + 13/52 + 39/51= 19/34
7)13/52 * 39/51 = 13/68
8) 4/52 * 3/51 + 13/52 * 12/51 + 4/52 * 12/51 + 1/51 =29/663

#5.Chose one of two tables below to create your own Question (with solution).

My Conditional Frequency Question is:

My solution (work and answer):

Please explain how/why you chose this question

Answers

Therefore , the solution of the given problem of unitary method comes out to be the likelihood that a particular child has a curfew given that they have tasks is 3/7, or roughly 0.43.

What is an unitary method?

The job can be completed by bringing together what was learned and applying this variable technique, that also includes all supplementary data from two people that utilized a specific tactic. To put it another way, if the desired outcome materialises, either the entity stated in the calculation will be recognised, or both expression essential processes will truly skip the colour. For forty pencils, a refundable charge of Rupees ($1.01) might be required.

Here,

Using the following formula, one can determine the conditional chance that a child will have a curfew if they have chores:

Curfew and duties are equal, so

=>P(curfew | chores) = P (chores)

The odds are listed in the table below:

=> Curfew and errands P = 3/10

=> P(tasks) = 7/9

Therefore,

=> P(curfew | chores)=3/10/ (7/10)=3/7

Therefore, the likelihood that a particular child has a curfew given that they have tasks is 3/7, or roughly 0.43.

To know more about unitary method visit:

brainly.com/question/28276953

#SPJ1

Halp pleaseee? list all possible rational roots for the equation 3x^4-5x^2+25=0 thanks :))

Answers

x= +[5/6(1+i√11)]
and
x= +[5/6(1-i√11)]

write 3 four times and multiple them together. Then, write out 5 two times and multiple it together. Whatever those two answers are, subtract them

What is 3/5 divided 2 1/2?

Answers

Answer:

6/25 or 0.24

Step-by-step explanation:

(3/5) / (2 1/2) =

(3/5) / (5/2) =

(3/5) × (2/5) =

6/25 = 0.24

Answer:

6/25

Step-by-step explanation:

I Divided 3/5 by 1/2

PLEASE ANSWER ASAP! YOUR ANSWER MUST REQUIRE AN EXPLANATION IN ORDER TO RECEIVE 10 POINTS AND THE BRAINLIEST ANSWER!!! THANKS!!!!

Answers

Hello,

Using vectors and scalar product:

$[(a+c)*\vec{i}+(b-0)*\vec{j} ].[(a-c)*\vec{i}+(b-0)*\vec{j}]=0$
Thus
$(b^2)/((a+c)(a-c))=1$

By the way how can we make text larger in latex \larger{.....} don't work.

Answer A

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