pathogenic bacteria
aerobic bacteria
rickettsia
Answer:
The correct answer would be nitrogen-fixing bacteria.
Nitrogen-fixing bacteria live in symbiotic relationship in the roots of plants especially leguminous plants such as peanuts, soybean, pulses et cetera.
The symbiotic bacteria live in the root nodules of the plants.
It helps in fixing the atmospheric nitrogen and converts into the forms which can be used by plants.
In return, plants provide the bacteria with shelter and food (glucose).
Example of symbiotic bacteria would be rhizobia
B. Heat stroke
C. Atherosclerosis
D.sickle cell anemia
Answer:
False
Explanation:
If it is a T or F questions then yes it is false.
Answer:
a) vertebra
Explanation:
A laminectomy is a surgical procedure performed to remove the lamina, a vertebral bone, in order to ease pressure on the spinal cord that causes back pain, numbness on the legs and even problems to control bladder or bowel movements.
I hope you find this information useful and interesting! Good luck!
Answer:
Explanation:
it depends on the total percentage of the population. that way we can pick out the percentage of the heterozygous
The percentage of the population that will be heterozygous (Ss) for sickle-cell and therefore resistant to malaria is 84%.
To calculate the percentage of the population that will be heterozygous (Ss) for sickle-cell and therefore resistant to malaria, we need to find the frequency of the ss genotype first. Given that 16% of the population is born with a severe form of sickle-cell anemia (ss), the frequency of the ss genotype is 0.16.
Since we are dealing with a single gene with two alleles, the sum of the frequencies of all possible genotypes should equal 1. So, to find the frequency of the Ss genotype, we can subtract the frequency of the ss genotype from 1.
Frequency of Ss = 1 - Frequency of ss = 1 - 0.16 = 0.84.
Finally, to get the percentage, we can multiply the frequency by 100.
Percentage of the population that will be heterozygous (Ss) = Frequency of Ss x 100 = 0.84 x 100 = 84%.
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