The freezing point of helium is -468 degrees Fahrenheit. If you increase that temperature by 569.7 degrees Fahrenheit, you reach the freezing point of phosphorus. What is the freezing point of phosphorus?

Answers

Answer 1

Answer:

The answer to your question would be that 101.7 is the freezing point of phosphorous.

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PLEASE HELP! Im not very good at math

Answers

Answer:

The answer provided is incorrect, the mistake is in the division between the monomials $x^{(6)/(5)}$ and $x^{(2)/(5)}$ that is equal to $x^{(4)/(5)$ not $x^3$ , because we must mantain the same base "x" and subtract the expoents that are $(6)/(5) - (2)/(5) = (4)/(5)$ .

Step-by-step explanation:

In order to simplify that question we need to multiply, divide and power monomials with the same base "x". When we multiply monomias with the same base we sum the expoents, to divide we subtract the expoents and to power them we multiply the expoents. Therefore to simplify the equations we must do:

$(\frac{x^{(2)/(5)}*x^{(4)/(5)}}{x^{(2)/(5)}})^(1)/(2)\n(\frac{x^{(6)/(5)}}{x^{(2)/(5)}})^(1)/(2)\n(x^{(4)/(5)})^(1)/(2)\nx^{(4)/(10)}\nx^{(2)/(5)}$

Answer:

No the answer is incorrect.

Step-by-step explanation:

From the question given;

( $X^{(2)/(5) }$ . $X^{(4)/(5) }$ / $X^{(2)/(5) }$ )¹/²

We will start by solving the inner bracket

By the law of indices $x^(a) . x^(b) = x^(a+b)$

$X^{(2)/(5) }$ . $X^{(4)/(5) }$ = $X^{(2)/(5)+(4)/(5) } = X^{(6)/(5) }$

we will replace $X^{(2)/(5) }$ . $X^{(4)/(5) }$ by $X^{(6)/(5) }$

$X^{(2)/(5) }$ . $X^{(4)/(5) }$ by $X^{(6)/(5) }$

( $X^{(2)/(5) }$ . $X^{(4)/(5) }$ / $X^{(2)/(5) }$ )¹/² = ( $X^{(6)/(5) }$ / $X^{(2)/(5) }$ )¹/²

By the law of indices $x^(a) /x^(b) = x^(a-b)$

$X^{(6)/(5) }$ / $X^{(2)/(5) }$ = $X^{(6)/(5) - (2)/(5) }$ = $X^{(4)/(5) }$

We will replace $X^{(6)/(5) }$ / $X^{(2)/(5) }$ by $X^{(4)/(5) }$

( $X^{(6)/(5) }$ / $X^{(2)/(5) }$ )¹/² = ( $X^{(4)/(5) }$ )¹/² = $X^{(4)/(10) }$ = $X^{(2)/(5) }$

( $X^{(2)/(5) }$ . $X^{(4)/(5) }$ / $X^{(2)/(5) }$ )¹/² = $X^{(2)/(5) }$

No the answer is incorrect.

He made a mistake, because $X^{(6)/(5) }$ / $X^{(2)/(5) }$ = = $X^{(6)/(5) - (2)/(5) }$ = $X^{(4)/(5) }$ and not equal to $x^(3)$

Could you guys please help me with these questions I give thanks

Answers

Triangular Prism:

$\sf~V=(1)/(2)*~l*~w*~h$

$\sf~V=(1)/(2)*7*3*3$

$\sf~V=3.5*3*3$

$\sf~V=10.5*3$

$\sf~V=31.5$

Break the Trapezoidal Prism into a rectangular prism with side measurements of 12, 18, and 6 and into a triangular prism with measurements of 6, 16, and 12.

Rectangular Prism:

$\sf~V=lwh$

$\sf~V=(12)(18)(6)$

Multiply all 3 numbers together:

$\sf~V=1296$

Now find the volume of the triangular prism:

$\sf~V=(1)/(2)lwh$

$\sf~V=(1)/(2)(6)(16)(12)$

Multiply all 4 numbers:

$\sf~V=576$

Add the two volumes together:

$\sf1296+576=1872$

Now we have to get rid of the area inside.

It's two rectangles both with lengths of 12 and widths of 6.

$\sf~A=lw$

$\sf~A=(12)(6)$

$\sf~A=72$

Multiply by 2 then subtract from the total volume we got:

$\sf~72*2 = 144$

Subtract it:

$\sf1872-144=1728$

Charlotte bought 16 songs for her MP3 player. Three-fourths of the songs are classical songs. How many of the songs are classical songs?

Answers

I think 8 are classical songs

12 songs because if you look at the problem there is the word “of”. The word of means multiply, so if you make 16 into fraction that is 61/1 and multiply that my 34 the word problem is,16/1 x 3/4= 48/4 and 48 over 4 is equal to 12 and that is 12 songs.

I am a fraction > 3/11 but < 4/11.
My numerator is 7. ________

Answers

First, we need to create a higher denominator.
3/11 = 6/22
4/11 = 8/22
Thus the only fraction between them is 7/22 which is the answer.

7 over 22 or 7\22 randomrandom

What is the value of 6x8-4[7+(8-3)] ?

Answers

0

PEMDAS

6*8-4[7+(8-3)]

6*8-4(7+5)

6*8-4(12)

6*8-48

48-48

0

Answer:

Step-by-step explanation:

The ratio of nitrogen to potassium in a sample to soil is 12:9. If the sample has 36 units of nitrogen, how much potassium does the sample have?

Answers

The ratio of nitrogen to potassium is said to be : 12 : 9
Now, the given sample for the units of nitrogen is 36.
Let's find out how much will be the value of potassium
.=> 12 : 9 = 36 : x , where x will be the value of the potassium.First, let's multiply the inner value of the proportion
=> 9 * 36 = 324
=> 324 / 12 = 27
Now, the ratio: 12 : 9 = 36 : 27

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